Identify the reaction and stoichiometry

Toluene is converted to benzaldehyde: $\mathrm{C_6H_5CH_3 \rightarrow C_6H_5CHO}$

This is a 1 : 1 molar conversion.

Calculate molar masses

• Toluene, $\mathrm{C_7H_8}$: $7 \times 12 + 8 \times 1 = 84 + 8 = 92\,\text{g mol}^{-1}$

• Benzaldehyde, $\mathrm{C_7H_6O}$: $7 \times 12 + 6 \times 1 + 16 = 84 + 6 + 16 = 106\,\text{g mol}^{-1}$

Find moles of toluene used

Given mass of toluene = $5\,\text{g}$ $n_{\text{toluene}} = \frac{5}{92}\,\text{mol}$

Theoretical mass of benzaldehyde

Since mole ratio is $1:1$, $n_{\text{benzaldehyde}} = \frac{5}{92}\,\text{mol}$

So theoretical mass of benzaldehyde is $m_{\text{theoretical}} = \frac{5}{92} \times 106$ $= 5.7609\,\text{g}$

Apply 92% yield

$m_{\text{actual}} = 5.7609 \times \frac{92}{100}$ $= 5.3000\,\text{g}$

Express in the required form

We need: $\underline{\hspace{2cm}} \times 10^{-2}\,\text{g}$

Since $5.3000\,\text{g} = 530 \times 10^{-2}\,\text{g}$

Hence, the required integer is: $\boxed{530}$