Sign in
12thPass logo
New chatPYQ LibraryDoubtsRank report
Sign in to see Recents

Your guest activity stays on this device

Sign in to save progress →
Sign in

Practical Organic Chemistry question

2022 · 28 Jun · Shift 1 · Q23
Guest · filters and generic practice availableBrowsing as a guest · PYQ filters and generic practice are available. Sign in only for personalised features and saved progress.
  1. PYQ Library
  2. /JEE Main
  3. /Chemistry
  4. /Practical Organic Chemistry
  5. /2022 · 28 Jun · Shift 1 · Q23

Practical Organic Chemistry question

2022 · 28 Jun · Shift 1 · Q23

JEE MainChemistryPractical Organic ChemistryNumerical+4 / −1
In the estimation of bromine, 0.5 g of an organic compound gave 0.40 g of silver bromide. The percentage of bromine in the given compound is ‾\underline{\hspace{2cm}}​ % (nearest integer) (Relative atomic masses of Ag and Br are 108u and 80u, respectively).
Numerical answer
View written solutionFree

Correct answer: 34

  1. Find the mass fraction of bromine in silver bromide

Silver bromide is AgBr\text{AgBr}AgBr.

Molar mass of AgBr\text{AgBr}AgBr: 108+80=188108 + 80 = 188108+80=188

Out of 188188188 g of AgBr\text{AgBr}AgBr, bromine contributes 808080 g.

So, mass of bromine in 0.400.400.40 g of AgBr\text{AgBr}AgBr is: mBr=0.40×80188m_{\text{Br}} = 0.40 \times \frac{80}{188}mBr​=0.40×18880​

  1. Calculate the bromine mass

mBr=0.40×80188=32188≈0.1702 gm_{\text{Br}} = 0.40 \times \frac{80}{188} = \frac{32}{188} \approx 0.1702\text{ g}mBr​=0.40×18880​=18832​≈0.1702 g

  1. Calculate percentage of bromine in the organic compound

Given mass of organic compound =0.50= 0.50=0.50 g.

Therefore, %Br=0.17020.50×100\%\text{Br} = \frac{0.1702}{0.50} \times 100%Br=0.500.1702​×100

%Br=34.04%\%\text{Br} = 34.04\%%Br=34.04%

  1. Nearest integer

34\boxed{34}34​

  1. Comparison with stored answer

Stored correct answer = 343434.

Our derived answer also is 343434, so they agree.

PreviousNext

More from Practical Organic Chemistry

  • In bromination of Propyne, with Bromine, 1, 1, 2, 2-tetrabromopropane is obtained in 27% yield. The amount of 1, 1, 2, 2-tetrabromopropane obtained from 1 g of Bromine in this reaction is ​× 10 − 1 g.…2022 · Numerical
  • Kjeldahl's method was used for the estimation of nitrogen in an organic compound. The ammonia evolved from 0.55 g of the compound neutralised 12.5 mL of 1 M H2​SO4​ solution. The percentage of nitrogen in the compound is ​…2022 · Numerical
  • The reagent neutral ferric chloride is used to detect the presence of ​2022 · MCQ
  • An organic compound with 51.6% sulfur is heated in a Carius tube. The amount of this compound which will form 0.752 g of barium sulphate is ​× 10 − 1 g. (Given molar mass of barium sulphate 233 g mol − 1)…2022 · Numerical
  • Match List - I with List - II : The correct match is : Includes table2021 · MCQ
  • In Duma's method of estimation of nitrogen, 0.1840 g of an organic compound gave 30 mL of nitrogen collected at 287 K and 758 mm of Hg pressure. The percentage composition of nitrogen in the compound is ​. (Round…2021 · Numerical
  • In the above reaction, 3.9 g of benzene on nitration gives 4.92 g of nitrobenzene. The percentage yield of nitrobenzene in the above reaction is ​%. (Round off to the Nearest Integer). (Given atomic mass : C : 12.0… Includes diagram2021 · Numerical
  • Reagent, 1-napthylamine and sulphanilic acid in acetic acid is used for the detection of2021 · MCQ