JEE MainChemistryPractical Organic ChemistryNumerical+4 / −1
A 2.0 g sample containing is treated with liberating . The gas is passed into a solution of and 60.0 mL of 0.1 M is required to titrate the liberated iodine. The percentage of in the sample is . (Nearest integer) [Atomic masses (in u) Mn = 55; Cl = 35.5; O = 16, I = 127, Na = 23, K = 39, S = 32]
Numerical answer
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