JEE MainChemistryPractical Organic ChemistryMCQ+4 / −1
The correct match between Item-I and Item-II is :
| Item-I (drug) | Item-II (test) | ||
|---|---|---|---|
| A | Chloroxylenol | P | Carbylamine test |
| B | Norethindrone | Q | Sodium hydrogen carbonet test |
| C | Sulphapyridine | R | Ferric chloride test |
| D | Penicillin | S | Bayer's test |
- AA R; B P; C S; D Q
- BA Q; B S; C P; D R
- CA R; B S; C P; D Q
- DA Q; B P; C S; D R
View written solutionFree
Correct answer: C
- Identify the functional group in each drug and match with the characteristic test.
- A. Chloroxylenol
Chloroxylenol is a phenolic compound. Phenols give a characteristic ferric chloride test.
So,
- B. Norethindrone
Norethindrone contains an unsaturated bond (a C=C bond in the steroid framework). Unsaturation is tested by Baeyer's test (alkaline ).
So,
- C. Sulphapyridine
Sulphapyridine is a sulfa drug containing a primary aromatic amino group. Primary amines respond to the carbylamine test.
So,
- D. Penicillin
Penicillin contains a carboxylic acid group. Carboxylic acids give effervescence with sodium hydrogen carbonate test.
So,
- Final matching
Thus the correct set is:
This corresponds to Option C.
- Comparison with stored answer
Stored correct answer = C
Derived answer = C
Hence, the derived answer agrees with the stored answer.
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