Sign in
12thPass logo
New chatPYQ LibraryDoubtsRank report
Sign in to see Recents

Your guest activity stays on this device

Sign in to save progress →
Sign in

P Block Elements question

2021 · 25 Jul · Shift 1 · Q10
Guest · filters and generic practice availableBrowsing as a guest · PYQ filters and generic practice are available. Sign in only for personalised features and saved progress.
  1. PYQ Library
  2. /JEE Main
  3. /Chemistry
  4. /P Block Elements
  5. /2021 · 25 Jul · Shift 1 · Q10

P Block Elements question

2021 · 25 Jul · Shift 1 · Q10

JEE MainChemistryP Block ElementsMCQ+4 / −1
Which one of the following compounds of Group-14 elements is not known?
  1. A
    [GeCl6]2−[GeCl_6]^{2-}[GeCl6​]2−
  2. B
    [Sn(OH)6]2−[Sn(OH)_6]^{2-}[Sn(OH)6​]2−
  3. C
    [SiCl6]2−[SiCl_6]^{2-}[SiCl6​]2−
  4. D
    [SiF6]2−[SiF_6]^{2-}[SiF6​]2−
View written solutionFree

Correct answer: C

  1. Key idea: tendency to form hexacoordinate complexes in Group 14

    Group 14 elements are: C, Si, Ge, Sn, Pb\text{C, Si, Ge, Sn, Pb}C, Si, Ge, Sn, Pb

    Their ability to expand coordination number increases down the group.

    • Si, Ge, Sn can form species with coordination number 6 in suitable cases.
    • However, this depends strongly on the ligand.

  2. Check each option

    Option A: [GeCl6]2−[GeCl_6]^{2-}[GeCl6​]2−

    Germanium can form hexahalogermanate complexes such as: [GeCl6]2−[GeCl_6]^{2-}[GeCl6​]2− This compound is known.

    Option B: [Sn(OH)6]2−[Sn(OH)_6]^{2-}[Sn(OH)6​]2−

    Tin(IV) forms hexahydroxostannate: [Sn(OH)6]2−[Sn(OH)_6]^{2-}[Sn(OH)6​]2− This is a well-known species in alkaline solution. So it is known.

    Option C: [SiCl6]2−[SiCl_6]^{2-}[SiCl6​]2−

    Silicon generally does not form a stable hexachloro complex of the type: [SiCl6]2−[SiCl_6]^{2-}[SiCl6​]2− because chlorine is larger and less effective than fluorine in stabilizing six-coordination around silicon. Hence this species is not known.

    Option D: [SiF6]2−[SiF_6]^{2-}[SiF6​]2−

    Hexafluorosilicate is a well-known ion: [SiF6]2−[SiF_6]^{2-}[SiF6​]2− It is known because fluorine, being very small and highly electronegative, stabilizes six-coordination around silicon.

  3. Conclusion

    The compound that is not known is: [SiCl6]2−[SiCl_6]^{2-}[SiCl6​]2−

  4. Comparison with stored answer

    Stored correct answer: C

    Our derived answer: C

    So the answer matches the stored correct answer.

PreviousNext

More from P Block Elements

  • Find A, B and C in the following reactions : NH3​+A+CO2​→(NH4​)2​CO3​(NH4​)2​CO3​+H2​O+B→NH4​HCO3​NH4​HCO3​+NaCl→NH4​Cl+C2021 · MCQ
  • Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R. Assertion A : In TlI3​, isomorphous to CsI3​, the metal is present in +1 oxidation state. Reason R : Tl metal has fourteen f…2021 · MCQ
  • In polythionic acid, H2​Sx​O6​ (x = 3 to 5) the oxidation state(s) of sulphur is/are :2021 · MCQ
  • Match List - I with List - II : Choose the correct answer from the options given below : Includes table2021 · MCQ
  • Given below are two statement : one is labelled as Assertion A and the other is labelled as Reason R. Assertion A : SO2​(g) is absorbed to a large extent than H2​(g) on activated charcoal. Reason R : SO2​(g) has a higher critical…2021 · MCQ
  • Boron and silicon of very high purity can be obtained through :2020 · MCQ
  • The correct statement with respect to dinitrogen is :2020 · MCQ
  • A metal (A) on heating in nitrogen gas gives compound B. B on treatment with H2​O gives a colourless gas which when passed through CuSO4​ solution gives a dark blue-violet coloured solution. A and B respectively, are :2020 · MCQ