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Ionic Equilibrium question

2022 · 27 Jun · Shift 2 · Q19
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  5. /2022 · 27 Jun · Shift 2 · Q19

Ionic Equilibrium question

2022 · 27 Jun · Shift 2 · Q19

JEE MainChemistryIonic EquilibriumNumerical+4 / −1
pH value of 0.001 M NaOH solution is ‾\underline{\hspace{2cm}}​.
Numerical answer
View written solutionFree

Correct answer: 11

  1. Given solution

    The solution is 0.001 M0.001\,\text{M}0.001M NaOH.

  2. Nature of NaOH

    NaOH is a strong base, so it dissociates completely:

    NaOH→Na++OH−\text{NaOH} \rightarrow \text{Na}^+ + \text{OH}^-NaOH→Na++OH−

    Therefore,

    [OH−]=0.001=10−3 M[\text{OH}^-] = 0.001 = 10^{-3}\,\text{M}[OH−]=0.001=10−3M

  3. Calculate pOH

    pOH=−log⁡[OH−]=−log⁡(10−3)=3\text{pOH} = -\log[\text{OH}^-] = -\log(10^{-3}) = 3pOH=−log[OH−]=−log(10−3)=3

  4. Use relation between pH and pOH

    At 25∘C25^\circ\text{C}25∘C,

    pH+pOH=14\text{pH} + \text{pOH} = 14pH+pOH=14

    So,

    pH=14−3=11\text{pH} = 14 - 3 = 11pH=14−3=11

  5. Final answer

    11\boxed{11}11​

  6. Comparison with stored correct answer

    Stored correct answer = 111111

    My derived answer also = 111111, so they match.

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