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Hydrocarbons question

2025 · 2 Apr · Shift 2 · Q2
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Hydrocarbons question

2025 · 2 Apr · Shift 2 · Q2

JEE MainChemistryHydrocarbonsMCQ+4 / −1

Match List - I with List - II.

List - I
(Reaction)
List - II
(Name of reaction)
(A) JEE Main 2025 (Online) 2nd April Evening Shift Chemistry - Hydrocarbons Question 5 English (I) Lucas reaction

(B)
ArN2+X−→HClCuArCl+N2↑+CuX\mathrm{ArN}_2^{+} \mathrm{X}^{-} \xrightarrow[\mathrm{HCl}]{\mathrm{Cu}} \mathrm{ArCl}+\mathrm{N}_2 \uparrow+\mathrm{CuX}ArN2+​X−CuHCl​ArCl+N2​↑+CuX

(II) Finkelstein
reaction

(C)
C2H5Br+NaI→ Acetone  Dry C2H5I+NaBr\mathrm{C}_2 \mathrm{H}_5 \mathrm{Br}+\mathrm{NaI} \xrightarrow[\text { Acetone }]{\text { Dry }} \mathrm{C}_2 \mathrm{H}_5 \mathrm{I}+\mathrm{NaBr}C2​H5​Br+NaI Dry  Acetone ​C2​H5​I+NaBr

(III)
Fittig reaction


(D)
CH3C(OH)(CH3)CH3→ZnCl2HClCH3C(Cl)(CH3)CH3\mathrm{CH}_3 \mathrm{C}(\mathrm{OH})\left(\mathrm{CH}_3\right) \mathrm{CH}_3 \xrightarrow[\mathrm{ZnCl}_2]{\mathrm{HCl}} \mathrm{CH}_3 \mathrm{C}(\mathrm{Cl})\left(\mathrm{CH}_3\right) \mathrm{CH}_3CH3​C(OH)(CH3​)CH3​HClZnCl2​​CH3​C(Cl)(CH3​)CH3​

(IV)
Gatterman
reaction

 Choose the correct answer from the options given below : \text { Choose the correct answer from the options given below : } Choose the correct answer from the options given below : 

  1. A
    (A)-(III), (B)-(II), (C)-(IV), (D)-(I)
  2. B
    (A)-(IV), (B)-(III), (C)-(I), (D)-(II)
  3. C
    (A)-(IV), (B)-(I), (C)-(II), (D)-(III)
  4. D
    (A)-(III), (B)-(IV), (C)-(II), (D)-(I)
View written solutionFree

Correct answer: D

  1. Identify each reaction in List-I

    We match the given reactions with their standard names.

  2. Reaction (B)

    ArN2+X−→HClCuArCl+N2+CuX\mathrm{ArN_2^+X^-} \xrightarrow[\mathrm{HCl}]{\mathrm{Cu}} \mathrm{ArCl} + \mathrm{N_2} + \mathrm{CuX}ArN2+​X−CuHCl​ArCl+N2​+CuX

    This is the replacement of diazonium group by chlorine using copper powder and HCl.

    This is Gattermann reaction.

    So, (B)→(IV)(B) \to (IV)(B)→(IV)

  3. Reaction (C)

    C2H5Br+NaI→dry acetoneC2H5I+NaBr\mathrm{C_2H_5Br + NaI \xrightarrow[dry\ acetone]{} C_2H_5I + NaBr}C2​H5​Br+NaIdry acetone​C2​H5​I+NaBr

    This is halogen exchange of alkyl halide using sodium iodide in dry acetone.

    This is Finkelstein reaction.

    So, (C)→(II)(C) \to (II)(C)→(II)

  4. Reaction (D)

    (CH3)3COH→ZnCl2HCl(CH3)3CCl\mathrm{(CH_3)_3COH \xrightarrow[ZnCl_2]{HCl} (CH_3)_3CCl}(CH3​)3​COHHClZnCl2​​(CH3​)3​CCl

    Conversion of alcohol into alkyl chloride using concentrated HCl and anhydrous ZnCl2\mathrm{ZnCl_2}ZnCl2​ is Lucas reaction.

    So, (D)→(I)(D) \to (I)(D)→(I)

  5. Reaction (A)

    Since the remaining reaction name is Fittig reaction, we get

    (A)→(III)(A) \to (III)(A)→(III)

    (Fittig reaction involves coupling of aryl halides with sodium in dry ether.)

  6. Final matching

    (A)−(III), (B)−(IV), (C)−(II), (D)−(I)(A)-(III),\ (B)-(IV),\ (C)-(II),\ (D)-(I)(A)−(III), (B)−(IV), (C)−(II), (D)−(I)

  7. Compare with options

    This corresponds to Option D.

  8. Comparison with stored answer

    Stored correct answer is D, which matches our derived answer.

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