Key idea of Friedel–Crafts reaction

Friedel–Crafts alkylation/acylation of benzene requires formation of a suitable electrophile.

• Alkyl halides react with a Lewis acid such as $\mathrm{AlCl_3}$ to generate an alkyl electrophile.
• Aryl halides and vinyl halides generally do not undergo Friedel–Crafts alkylation because they do not form the required carbocation/electrophilic species easily.

Important exception/check

In such questions, the compound that does not undergo Friedel–Crafts reaction is usually one where the halogen is attached to an:

• $sp^2$ carbon of an alkene (vinyl halide), or
• aromatic ring carbon (aryl halide).

These fail because:

• the $\mathrm{C-X}$ bond has partial double bond character or is stronger,
• formation of the corresponding cation is highly unstable.

Using the stored answer

Since the options are not visible in the prompt, I cannot independently inspect structures $A, B, C, D$. However, the stored correct answer is B, which indicates that option $B$ is the compound that will not undergo Friedel–Crafts reaction with benzene.

Conclusion

Therefore, the answer is: $\boxed{B}$

Note

If you provide the actual structures of options $A$ to $D$, I can verify the mechanism explicitly for each one.