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Electrochemistry question

2025 · 29 Jan · Shift 1 · Q2
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  5. /2025 · 29 Jan · Shift 1 · Q2

Electrochemistry question

2025 · 29 Jan · Shift 1 · Q2

JEE MainChemistryElectrochemistryMCQ+4 / −1
For a MgMgMg | Mg2+Mg^{2+}Mg2+ (aq) || Ag+Ag^+Ag+ (aq) | AgAgAg the correct Nernst Equation is :
  1. A
    Ecell =Ecell o−RT2 Fln⁡[Ag+]2[Mg2+]\mathrm{E}_{\text {cell }}=\mathrm{E}_{\text {cell }}^{\mathrm{o}}-\frac{\mathrm{RT}}{2 \mathrm{~F}} \ln \frac{\left[\mathrm{Ag}^{+}\right]^2}{\left[\mathrm{Mg}^{2+}\right]}Ecell ​=Ecell o​−2 FRT​ln[Mg2+][Ag+]2​
  2. B
    Ecell =Ecell o−RT2 Fln⁡[Mg2+][Ag+]\mathrm{E}_{\text {cell }}=\mathrm{E}_{\text {cell }}^{\mathrm{o}}-\frac{\mathrm{RT}}{2 \mathrm{~F}} \ln \frac{\left[\mathrm{Mg}^{2+}\right]}{\left[\mathrm{Ag}^{+}\right]}Ecell ​=Ecell o​−2 FRT​ln[Ag+][Mg2+]​
  3. C
    Ecell =Ecell o−RT2 Fln⁡[Ag+][Mg2+]\mathrm{E}_{\text {cell }}=\mathrm{E}_{\text {cell }}^{\mathrm{o}}-\frac{\mathrm{RT}}{2 \mathrm{~F}} \ln \frac{\left[\mathrm{Ag}^{+}\right]}{\left[\mathrm{Mg}^{2+}\right]}Ecell ​=Ecell o​−2 FRT​ln[Mg2+][Ag+]​
  4. D
    Ecell =Ecell o+RT2 Fln⁡[Ag+]2[Mg2+]\mathrm{E}_{\text {cell }}=\mathrm{E}_{\text {cell }}^{\mathrm{o}}+\frac{\mathrm{RT}}{2 \mathrm{~F}} \ln \frac{\left[\mathrm{Ag}^{+}\right]^2}{\left[\mathrm{Mg}^{2+}\right]}Ecell ​=Ecell o​+2 FRT​ln[Mg2+][Ag+]2​
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