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Electrochemistry question

2024 · 5 Apr · Shift 1 · Q18
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  5. /2024 · 5 Apr · Shift 1 · Q18

Electrochemistry question

2024 · 5 Apr · Shift 1 · Q18

JEE MainChemistryElectrochemistryMCQ+4 / −1
The reaction at cathode in the cells commonly used in clocks involves.
  1. A
    oxidation of Mn\mathrm{Mn}Mn from +2 to +7
  2. B
    reduction of Mn\mathrm{Mn}Mn from +4 to +3
  3. C
    oxidation of Mn\mathrm{Mn}Mn from +3 to +4
  4. D
    reduction of Mn\mathrm{Mn}Mn from +7 to +2
View written solutionFree

Correct answer: B

  1. Identify the cell commonly used in clocks

    The cells commonly used in clocks are dry cells / alkaline cells.

    In these cells, the cathode material is typically manganese dioxide, MnO2\mathrm{MnO_2}MnO2​.

  2. Determine the cathode reaction

    At the cathode, reduction always occurs.

    In the dry cell, manganese dioxide is reduced approximately as:

    MnO2+H2O+e−→MnO(OH)\mathrm{MnO_2 + H_2O + e^- \rightarrow MnO(OH)}MnO2​+H2​O+e−→MnO(OH)

    or equivalently, manganese changes from oxidation state +4+4+4 in MnO2\mathrm{MnO_2}MnO2​ to +3+3+3 in the reduced product.

  3. Check oxidation states of manganese

    • In MnO2\mathrm{MnO_2}MnO2​: x+2(−2)=0⇒x=+4x + 2(-2) = 0 \Rightarrow x = +4x+2(−2)=0⇒x=+4

    • In the reduced form, manganese becomes approximately +3+3+3.

    So the cathode process is:

    Mn+4→Mn+3\mathrm{Mn^{+4} \rightarrow Mn^{+3}}Mn+4→Mn+3

    which is a reduction.

  4. Evaluate the options

    • A: oxidation of Mn\mathrm{Mn}Mn from +2+2+2 to +7+7+7
      Incorrect.
    • B: reduction of Mn\mathrm{Mn}Mn from +4+4+4 to +3+3+3
      Correct.
    • C: oxidation of Mn\mathrm{Mn}Mn from +3+3+3 to +4+4+4
      Incorrect.
    • D: reduction of Mn\mathrm{Mn}Mn from +7+7+7 to +2+2+2
      Incorrect.
  5. Final answer

    The reaction at cathode involves reduction of manganese from +4+4+4 to +3+3+3.

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