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Electrochemistry question

2022 · 26 Jun · Shift 2 · Q21

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JEE Main
Chemistry
Electrochemistry
2022 · 26 Jun · Shift 2 · Q21

Electrochemistry question

2022 · 26 Jun · Shift 2 · Q21

JEE MainChemistryElectrochemistryNumerical+4 / −1

Cu

(s) +

Sn^{2+}

(0.001M)

\to

Cu^{2+}

(0.01M) +

Sn

(s) The Gibbs free energy change for the above reaction at 298 K is x

\times

10

-

1 kJ mol

-

1. The value of x is

\underline{\hspace{2cm}}

. [nearest integer] [Given :

E_{C{u^{2 + }}/Cu}^\Theta = 0.34\,V

;

E_{S{n^{2 + }}/Sn}^\Theta = - 0.14\,V

; F = 96500 C mol

-

1]

Numerical answer

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