Sign in
12thPass logo
New chatPYQ LibraryDoubtsRank report
Sign in to see Recents

Your guest activity stays on this device

Sign in to save progress →
Sign in

Electrochemistry question

2002 · Shift 0 · Q35
Guest · filters and generic practice availableBrowsing as a guest · PYQ filters and generic practice are available. Sign in only for personalised features and saved progress.
  1. PYQ Library
  2. /JEE Main
  3. /Chemistry
  4. /Electrochemistry
  5. /2002 · Shift 0 · Q35

Electrochemistry question

2002 · Shift 0 · Q35

JEE MainChemistryElectrochemistryMCQ+4 / −1
When the sample of copper with zinc impurity is to be purified by electrolysis, the appropriate electrodes are :
  1. A
    cathode = pure zinc, anode = pure copper
  2. B
    cathode = impure sample, anode = pure copper
  3. C
    cathode = impure zinc, anode = impure sample
  4. D
    cathode = pure copper, anode = impure sample
View written solutionFree

Correct answer: D

  1. Principle of electrolytic refining

In electrolytic purification of a metal:

  • Anode = impure metal
  • Cathode = pure metal sheet of the same metal
  • Electrolyte contains a soluble salt of that metal.

For copper purification:

  • Impure copper dissolves at the anode: Cu→Cu2++2e−\mathrm{Cu \rightarrow Cu^{2+} + 2e^-}Cu→Cu2++2e−
  • Pure copper is deposited at the cathode: Cu2++2e−→Cu\mathrm{Cu^{2+} + 2e^- \rightarrow Cu}Cu2++2e−→Cu
  1. Apply to the given case

The sample is copper containing zinc impurity. Since we want to purify copper, the setup must be:

  • Anode = impure sample of copper
  • Cathode = pure copper
  1. Check the options
  • A: cathode = pure zinc, anode = pure copper
    Wrong, because cathode should be pure copper, not zinc.

  • B: cathode = impure sample, anode = pure copper
    Wrong, because in refining the impure metal is made anode, not cathode.

  • C: cathode = impure zinc, anode = impure sample
    Wrong, because cathode should be pure copper.

  • D: cathode = pure copper, anode = impure sample
    Correct. This matches the standard electrolytic refining arrangement.

  1. Final answer

Therefore, the appropriate electrodes are: cathode = pure copper, anode = impure sample\boxed{\text{cathode = pure copper, anode = impure sample}}cathode = pure copper, anode = impure sample​ So, Option D is correct.

PreviousNext

More from Electrochemistry

  • For a cell given below Ag++e−Cu2++2e−​⟶Ag;E∘=x⟶Cu;E∘=y​ E∘ cell is … Includes diagram2002 · MCQ
  • Consider the following electrochemical cell at standard condition. Au( s)∣QH2​,Q∣NH4​X(0.01M)∣∣Ag+(1M)∣Ag( s)Ecell ​=+0.4 V… Includes diagram2025 · Numerical
  • 0.2%(w/v) solution of NaOH is measured to have resistivity 870.0 mΩ m. The molar conductivity of the solution will be ​×102mSdm2 mol−1…2025 · Numerical
  • Correct order of limiting molar conductivity for cations in water at 298 K is :2025 · MCQ
  • The standard cell potential (Ecell ⊖​) of a fuel cell based on the oxidation of methanol in air that has been used to power television relay station is measured as 1.21 V . The standard half cell…2025 · MCQ
  • On charging the lead storage battery, the oxidation state of lead changes from x1​ to y1​ at the anode and from x2​ to y2​ at the cathode. The values of x1​,y1​,x2​,y2​ are respectively :2025 · MCQ
  • 1 Faraday electricity was passed through Cu2+(1.5M,1 L)/Cu and 0.1 Faraday was passed through Ag+(0.2M,1 L)/Ag electrolytic cells. After this the… Includes diagram2025 · Numerical
  • Given below are two statements : 1 M aqueous solutions of each of Cu(NO3​)2​, AgNO3​, Hg2​(NO3​)2​, Mg(NO3​)2​ are electrolysed using inert electrodes. Given: E0Ag+/Ag = 0.80 V, E0Hg22+​/Hg = 0.79 V, E0Cu2+/Cu = 0.24 V…2025 · MCQ