Given below are two statements: Statement I : CrO_3 is a stronger oxidizing agent than MoO_3 Statement II : Cr(VI) is more stable than Mo(VI) In the light of the above statements, choose the correct answer from the options given below

Statement I is true but Statement II is false

Both Statement I and Statement II are true

Both Statement I and Statement II are false

Statement I is false but Statement II is true

D and F Block Elements PYQ — JEE Main 2025 · 3 Apr · Shift 2 · Q10 with Solution

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Correct answer: A

Analyze Statement I

Statement I: $\mathrm{CrO}_3$ is a stronger oxidizing agent than $\mathrm{MoO}_3$ .
- In group 6 elements, the oxidizing character of the highest oxidation state oxides decreases down the group.
- Chromium is smaller and its $+6$ state is less stable compared to molybdenum.
- Therefore, $\mathrm{Cr}(VI)$ compounds such as $\mathrm{CrO}_3$ more readily get reduced, so they act as stronger oxidizing agents than $\mathrm{MoO}_3$ .
Hence, Statement I is true.
Analyze Statement II

Statement II: $\mathrm{Cr}(VI)$ is more stable than $\mathrm{Mo}(VI)$ .
- Down the group from Cr to Mo to W, higher oxidation states become more stable.
- Thus, $\mathrm{Mo}(VI)$ is more stable than $\mathrm{Cr}(VI)$ , not the other way around.
Hence, Statement II is false.
Choose the correct option
- Statement I: True
- Statement II: False
Therefore, the correct option is: $\boxed{\text{A}}$
Comparison with stored answer

Stored correct answer: $\text{A}$

My derived answer matches the stored answer.

View written solutionFree

Correct answer: A

Analyze Statement I

Statement I: $\mathrm{CrO}_3$ is a stronger oxidizing agent than $\mathrm{MoO}_3$ .
- In group 6 elements, the oxidizing character of the highest oxidation state oxides decreases down the group.
- Chromium is smaller and its $+6$ state is less stable compared to molybdenum.
- Therefore, $\mathrm{Cr}(VI)$ compounds such as $\mathrm{CrO}_3$ more readily get reduced, so they act as stronger oxidizing agents than $\mathrm{MoO}_3$ .
Hence, Statement I is true.
Analyze Statement II

Statement II: $\mathrm{Cr}(VI)$ is more stable than $\mathrm{Mo}(VI)$ .
- Down the group from Cr to Mo to W, higher oxidation states become more stable.
- Thus, $\mathrm{Mo}(VI)$ is more stable than $\mathrm{Cr}(VI)$ , not the other way around.
Hence, Statement II is false.
Choose the correct option
- Statement I: True
- Statement II: False
Therefore, the correct option is: $\boxed{\text{A}}$
Comparison with stored answer

Stored correct answer: $\text{A}$

My derived answer matches the stored answer.