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D and F Block Elements question

2023 · 31 Jan · Shift 1 · Q5
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  5. /2023 · 31 Jan · Shift 1 · Q5

D and F Block Elements question

2023 · 31 Jan · Shift 1 · Q5

JEE MainChemistryD and F Block ElementsMCQ+4 / −1
The correct order of basicity of oxides of vanadium is :
  1. A
    V2O3>V2O5>V2O4\mathrm{V_2O_3 \gt V_2O_5 \gt V_2O_4}V2​O3​>V2​O5​>V2​O4​
  2. B
    V2O3>V2O4>V2O5\mathrm{V_2O_3 \gt V_2O_4 \gt V_2O_5}V2​O3​>V2​O4​>V2​O5​
  3. C
    V2O5>V2O4>V2O3\mathrm{V_2O_5 \gt V_2O_4 \gt V_2O_3}V2​O5​>V2​O4​>V2​O3​
  4. D
    V2O4>V2O3>V2O5\mathrm{V_2O_4 \gt V_2O_3 \gt V_2O_5}V2​O4​>V2​O3​>V2​O5​
View written solutionFree

Correct answer: B

  1. Identify oxidation states of vanadium in the oxides

  • In V2O3\mathrm{V_2O_3}V2​O3​: 2x+3(−2)=0⇒2x−6=0⇒x=+32x + 3(-2) = 0 \Rightarrow 2x - 6 = 0 \Rightarrow x = +32x+3(−2)=0⇒2x−6=0⇒x=+3 So vanadium is in the +3+3+3 oxidation state.

  • In V2O4\mathrm{V_2O_4}V2​O4​: 2x+4(−2)=0⇒2x−8=0⇒x=+42x + 4(-2) = 0 \Rightarrow 2x - 8 = 0 \Rightarrow x = +42x+4(−2)=0⇒2x−8=0⇒x=+4 So vanadium is in the +4+4+4 oxidation state.

  • In V2O5\mathrm{V_2O_5}V2​O5​: 2x+5(−2)=0⇒2x−10=0⇒x=+52x + 5(-2) = 0 \Rightarrow 2x - 10 = 0 \Rightarrow x = +52x+5(−2)=0⇒2x−10=0⇒x=+5 So vanadium is in the +5+5+5 oxidation state.

  1. Use the trend of acid-base character of transition metal oxides

For a given metal, as the oxidation state increases:

  • basic character decreases
  • acidic character increases

This is because higher oxidation state gives greater polarizing power to the metal ion, making the oxide more covalent and acidic.

So for vanadium oxides: Basicity: V3+extoxide>V4+extoxide>V5+extoxide\text{Basicity: } \mathrm{V^{3+} ext{ oxide} > V^{4+} ext{ oxide} > V^{5+} ext{ oxide}}Basicity: V3+extoxide>V4+extoxide>V5+extoxide

Therefore, V2O3>V2O4>V2O5\mathrm{V_2O_3 > V_2O_4 > V_2O_5}V2​O3​>V2​O4​>V2​O5​

  1. Match with the options
  • A: V2O3>V2O5>V2O4\mathrm{V_2O_3 > V_2O_5 > V_2O_4}V2​O3​>V2​O5​>V2​O4​ ❌
  • B: V2O3>V2O4>V2O5\mathrm{V_2O_3 > V_2O_4 > V_2O_5}V2​O3​>V2​O4​>V2​O5​ ✅
  • C: V2O5>V2O4>V2O3\mathrm{V_2O_5 > V_2O_4 > V_2O_3}V2​O5​>V2​O4​>V2​O3​ ❌
  • D: V2O4>V2O3>V2O5\mathrm{V_2O_4 > V_2O_3 > V_2O_5}V2​O4​>V2​O3​>V2​O5​ ❌
  1. Final answer

The correct order of basicity is: V2O3>V2O4>V2O5\boxed{\mathrm{V_2O_3 > V_2O_4 > V_2O_5}}V2​O3​>V2​O4​>V2​O5​​ So the correct option is B.

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