Given below are two statements : Statement (I) : In octahedral complexes, when \Delta_0P low spin complexes are formed. Statement (II) : In tetrahedral complexes because of \Delta_t In the light of the above statements, choose the most appropriate answer from the options given below :

Both Statement I and Statement II are correct

Both Statement I and Statement II are incorrect

Statement I is correct but Statement II is incorrect

Statement I is incorrect but Statement II is correct

Coordination Compounds PYQ — JEE Main 2025 · 2 Apr · Shift 1 · Q9 with Solution

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Correct answer: D

Interpret Statement (I)

The statement is clearly referring to the usual criterion for high spin/low spin in octahedral complexes:
- If the crystal field splitting energy is greater than pairing energy, i.e. $\Delta_o > P,$ electrons prefer to pair in the lower-energy $t_{2g}$ orbitals.
- Hence, low spin complexes are formed.
Therefore, Statement (I) is correct.
Interpret Statement (II)

For tetrahedral complexes, the crystal field splitting is much smaller than in octahedral complexes: $\Delta_t = \frac{4}{9}\Delta_o$ so generally, $\Delta_t < P.$

Because the splitting is small compared to pairing energy, electrons prefer to remain unpaired rather than pair up. Thus, tetrahedral complexes are generally high spin.

So the intended Statement (II) is also correct.
Choose the correct option
- Statement (I): Correct
- Statement (II): Correct
Hence, the correct option is: D: Both Statement I and Statement II are correct.
Comparison with stored answer

Stored correct answer: D

Our derived answer: D

They match.

View written solutionFree

Correct answer: D

Interpret Statement (I)

The statement is clearly referring to the usual criterion for high spin/low spin in octahedral complexes:
- If the crystal field splitting energy is greater than pairing energy, i.e. $\Delta_o > P,$ electrons prefer to pair in the lower-energy $t_{2g}$ orbitals.
- Hence, low spin complexes are formed.
Therefore, Statement (I) is correct.
Interpret Statement (II)

For tetrahedral complexes, the crystal field splitting is much smaller than in octahedral complexes: $\Delta_t = \frac{4}{9}\Delta_o$ so generally, $\Delta_t < P.$

Because the splitting is small compared to pairing energy, electrons prefer to remain unpaired rather than pair up. Thus, tetrahedral complexes are generally high spin.

So the intended Statement (II) is also correct.
Choose the correct option
- Statement (I): Correct
- Statement (II): Correct
Hence, the correct option is: D: Both Statement I and Statement II are correct.
Comparison with stored answer

Stored correct answer: D

Our derived answer: D

They match.