Choose the correct statements from the following : (A) Ethane-1, 2-diamine is a chelating ligand. (B) Metallic aluminium is produced by electrolysis of aluminium oxide in presence of cryolite. (C) Cyanide ion is used as ligand for leaching of silver. (D) Phosphine act as a ligand in Wilkinson catalyst. (E) The stability constants of Ca^2+ and Mg^2+ are similar with EDTA complexes. Choose the correct answer from the options given below :

Coordination Compounds PYQ — JEE Main 2024 · 30 Jan · Shift 1 · Q16 with Solution

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Correct answer: THE CORRECT SET SHOULD BE (A), (B), (C), AND (D). THE STORED ANSWER D MISSES STATEMENT (D), WHICH IS TRUE BECAUSE WILKINSON CATALYST IS RHCL(PPH3)3 CONTAINING PHOSPHINE LIGAND(S).

Evaluate statement (A): Ethane-1,2-diamine is a chelating ligand
Ethane-1,2-diamine (en) has two donor nitrogen atoms and can bind to the same metal ion through both N atoms, forming a ring. Hence it is a bidentate chelating ligand.
Therefore, (A) is correct.
Evaluate statement (B): Metallic aluminium is produced by electrolysis of aluminium oxide in presence of cryolite
In the Hall–Héroult process, aluminium is extracted by electrolysis of alumina, $\mathrm{Al_2O_3}$ , dissolved in molten cryolite, $\mathrm{Na_3AlF_6}$ . Cryolite lowers the melting point and increases conductivity.
Therefore, (B) is correct.
Evaluate statement (C): Cyanide ion is used as ligand for leaching of silver
Silver is extracted by cyanide process, where $\mathrm{CN^-}$ forms the complex: $\mathrm{4Ag + 8CN^- + O_2 + 2H_2O \rightarrow 4[Ag(CN)_2]^- + 4OH^-}$ Thus cyanide acts as a ligand in leaching of silver.
Therefore, (C) is correct.
Evaluate statement (D): Phosphine act as a ligand in Wilkinson catalyst
Wilkinson catalyst is: $\mathrm{RhCl(PPh_3)_3}$ The ligand present is triphenylphosphine ( $\mathrm{PPh_3}$ ), which is a phosphine ligand. So phosphine-type ligand does act in Wilkinson catalyst.
Therefore, (D) is correct.
Evaluate statement (E): The stability constants of $\mathrm{Ca^{2+}}$ and $\mathrm{Mg^{2+}}$ are similar with EDTA complexes
The stability constants are not similar; EDTA forms noticeably more stable complex with $\mathrm{Ca^{2+}}$ than with $\mathrm{Mg^{2+}}$ in standard tabulations used at this level. Hence this statement is taken as incorrect.
Therefore, (E) is incorrect.
Select the matching option
Correct statements are: $\boxed{(A), (B), (C), (D)}$

Now compare with options:
- A: $(B),(C),(E)$ only — incorrect
- B: $(A),(D),(E)$ only — incorrect
- C: $(C),(D),(E)$ only — incorrect
- D: $(A),(B),(C)$ only — missing (D)
Comparison with stored answer
The stored correct answer is D, but statement (D) is clearly correct because Wilkinson catalyst contains triphenylphosphine ligands. Hence none of the options exactly matches the true set of correct statements.

Conclusion: The given option set appears flawed. The correct statements should be (A), (B), (C), and (D).

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Correct answer: THE CORRECT SET SHOULD BE (A), (B), (C), AND (D). THE STORED ANSWER D MISSES STATEMENT (D), WHICH IS TRUE BECAUSE WILKINSON CATALYST IS RHCL(PPH3)3 CONTAINING PHOSPHINE LIGAND(S).

Evaluate statement (A): Ethane-1,2-diamine is a chelating ligand
Ethane-1,2-diamine (en) has two donor nitrogen atoms and can bind to the same metal ion through both N atoms, forming a ring. Hence it is a bidentate chelating ligand.
Therefore, (A) is correct.
Evaluate statement (B): Metallic aluminium is produced by electrolysis of aluminium oxide in presence of cryolite
In the Hall–Héroult process, aluminium is extracted by electrolysis of alumina, $\mathrm{Al_2O_3}$ , dissolved in molten cryolite, $\mathrm{Na_3AlF_6}$ . Cryolite lowers the melting point and increases conductivity.
Therefore, (B) is correct.
Evaluate statement (C): Cyanide ion is used as ligand for leaching of silver
Silver is extracted by cyanide process, where $\mathrm{CN^-}$ forms the complex: $\mathrm{4Ag + 8CN^- + O_2 + 2H_2O \rightarrow 4[Ag(CN)_2]^- + 4OH^-}$ Thus cyanide acts as a ligand in leaching of silver.
Therefore, (C) is correct.
Evaluate statement (D): Phosphine act as a ligand in Wilkinson catalyst
Wilkinson catalyst is: $\mathrm{RhCl(PPh_3)_3}$ The ligand present is triphenylphosphine ( $\mathrm{PPh_3}$ ), which is a phosphine ligand. So phosphine-type ligand does act in Wilkinson catalyst.
Therefore, (D) is correct.
Evaluate statement (E): The stability constants of $\mathrm{Ca^{2+}}$ and $\mathrm{Mg^{2+}}$ are similar with EDTA complexes
The stability constants are not similar; EDTA forms noticeably more stable complex with $\mathrm{Ca^{2+}}$ than with $\mathrm{Mg^{2+}}$ in standard tabulations used at this level. Hence this statement is taken as incorrect.
Therefore, (E) is incorrect.
Select the matching option
Correct statements are: $\boxed{(A), (B), (C), (D)}$

Now compare with options:
- A: $(B),(C),(E)$ only — incorrect
- B: $(A),(D),(E)$ only — incorrect
- C: $(C),(D),(E)$ only — incorrect
- D: $(A),(B),(C)$ only — missing (D)
Comparison with stored answer
The stored correct answer is D, but statement (D) is clearly correct because Wilkinson catalyst contains triphenylphosphine ligands. Hence none of the options exactly matches the true set of correct statements.

Conclusion: The given option set appears flawed. The correct statements should be (A), (B), (C), and (D).

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