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Coordination Compounds question

2024 · 30 Jan · Shift 2 · Q18
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  5. /2024 · 30 Jan · Shift 2 · Q18

Coordination Compounds question

2024 · 30 Jan · Shift 2 · Q18

JEE MainChemistryCoordination CompoundsMCQ+4 / −1
The coordination geometry around the manganese in decacarbonyldimanganese (0)(0)(0) is
  1. A
    Trigonal bipyramidal
  2. B
    Square pyramidal
  3. C
    Square planar
  4. D
    Octahedral
View written solutionFree

Correct answer: D

  1. Identify the compound

    Decacarbonyldimanganese (0)(0)(0) is: Mn2(CO)10\mathrm{Mn_2(CO)_{10}}Mn2​(CO)10​

    It consists of two manganese atoms bonded together, with a total of 10 carbonyl ligands.

  2. Determine the environment around each Mn atom

    In Mn2(CO)10\mathrm{Mn_2(CO)_{10}}Mn2​(CO)10​, the structure is:

    • Each Mn is bonded to 5 CO ligands
    • The two Mn atoms are also bonded to each other by an Mn--Mn bond

    So, around each manganese, the coordination count is: 5 CO ligands+1 Mn atom=65\text{ CO ligands} + 1\text{ Mn atom} = 65 CO ligands+1 Mn atom=6

    Thus, each Mn has six neighboring atoms/groups around it.

  3. Infer the geometry

    A coordination number of 6 generally corresponds to octahedral geometry.

    Here, each Mn is surrounded octahedrally by:

    • five carbonyl ligands
    • one manganese atom
  4. Check the options

    • A: Trigonal bipyramidal →\rightarrow→ coordination number 5, so incorrect
    • B: Square pyramidal →\rightarrow→ coordination number 5, so incorrect
    • C: Square planar →\rightarrow→ coordination number 4, so incorrect
    • D: Octahedral →\rightarrow→ coordination number 6, correct
  5. Final answer

    The coordination geometry around each manganese in Mn2(CO)10\mathrm{Mn_2(CO)_{10}}Mn2​(CO)10​ is: Octahedral\boxed{\text{Octahedral}}Octahedral​

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