Sign in
12thPass logo
New chatPYQ LibraryDoubtsRank report
Sign in to see Recents

Your guest activity stays on this device

Sign in to save progress →
Sign in

Coordination Compounds question

2023 · 30 Jan · Shift 1 · Q6
Guest · filters and generic practice availableBrowsing as a guest · PYQ filters and generic practice are available. Sign in only for personalised features and saved progress.
  1. PYQ Library
  2. /JEE Main
  3. /Chemistry
  4. /Coordination Compounds
  5. /2023 · 30 Jan · Shift 1 · Q6

Coordination Compounds question

2023 · 30 Jan · Shift 1 · Q6

JEE MainChemistryCoordination CompoundsMCQ+4 / −1
Which of the following is correct order of ligand field strength?
  1. A
    S2−<C2O42−<NH3<\mathrm{S}^{2-}\lt \mathrm{C}_{2} \mathrm{O}_{4}^{2-}\lt \mathrm{NH}_{3} \ltS2−<C2​O42−​<NH3​< en <CO\lt \mathrm{CO}<CO
  2. B
    CO<en<NH3<C2O42<S2−\mathrm{CO}\lt \mathrm{en}\lt \mathrm{NH}_{3}\lt \mathrm{C}_{2} \mathrm{O}_{4}^{2}\lt \mathrm{S}^{2-}CO<en<NH3​<C2​O42​<S2−
  3. C
    S2−<NH3<\mathrm{S}^{2-}\lt \mathrm{NH}_{3}\ltS2−<NH3​< en <CO<C2O42\lt \mathrm{CO}\lt \mathrm{C}_{2} \mathrm{O}_{4}^{2}<CO<C2​O42​
  4. D
    NH3<en<CO<S2−<C2O42\mathrm{NH}_{3}\lt \mathrm{en}\lt \mathrm{CO}\lt \mathrm{S}^{2-}\lt \mathrm{C}_{2} \mathrm{O}_{4}^{2}NH3​<en<CO<S2−<C2​O42​
View written solutionFree

Correct answer: A

  1. We need the order of ligand field strength, which is given by the spectrochemical series.

  2. Relevant part of the spectrochemical series is:

S2−<C2O42−<H2O<NH3<en<NO2−<CN−<CO\mathrm{S}^{2-} < \mathrm{C_2O_4}^{2-} < \mathrm{H_2O} < \mathrm{NH_3} < \text{en} < \mathrm{NO_2^-} < \mathrm{CN^-} < \mathrm{CO}S2−<C2​O4​2−<H2​O<NH3​<en<NO2−​<CN−<CO
  1. Now compare the ligands given in the options:
  • S2−\mathrm{S}^{2-}S2− is a weak-field ligand.
  • C2O42−\mathrm{C_2O_4}^{2-}C2​O4​2− (oxalate) is stronger than S2−\mathrm{S}^{2-}S2− but weaker than NH3\mathrm{NH_3}NH3​.
  • NH3\mathrm{NH_3}NH3​ is a stronger ligand than oxalate.
  • en (ethylenediamine) is slightly stronger than NH3\mathrm{NH_3}NH3​.
  • CO\mathrm{CO}CO is a very strong-field ligand.

So the correct increasing order is:

S2−<C2O42−<NH3<en<CO\mathrm{S}^{2-} < \mathrm{C_2O_4}^{2-} < \mathrm{NH_3} < \text{en} < \mathrm{CO}S2−<C2​O4​2−<NH3​<en<CO
  1. Check options:
  • A: S2−<C2O42−<NH3<en<CO\mathrm{S}^{2-} < \mathrm{C_2O_4}^{2-} < \mathrm{NH_3} < \text{en} < \mathrm{CO}S2−<C2​O4​2−<NH3​<en<CO ✅
  • B: reverse-type incorrect order ❌
  • C: places C2O42−\mathrm{C_2O_4}^{2-}C2​O4​2− stronger than CO\mathrm{CO}CO ❌
  • D: puts S2−\mathrm{S}^{2-}S2− stronger than CO\mathrm{CO}CO ❌

Hence, Option A is correct.

PreviousNext

More from Coordination Compounds

  • Match List I with List II: Includes table2023 · MCQ
  • The Cl−Co−Cl bond angle values in a fac-[Co(NH3​)3​Cl3​] complex is/are :2023 · MCQ
  • Cobalt chloride when dissolved in water forms pink colored complex X​ which has octahedral geometry. This solution on treating with conc HCl forms deep blue complex, Y​ which has a Z​…2023 · MCQ
  • If the CFSE of [Ti(H2​O)6​]3+ is −96.0 kJ/mol, this complex will absorb maximum at wavelength ​nm. (nearest integer) Assume…2023 · Numerical
  • In the cobalt-carbonyl complex : [Co2​(CO)8​], number of Co-Co bonds is "X" and terminal CO ligands is "Y". X + Y = ​.2022 · Numerical
  • Match List - I with List - II : Choose the most appropriate answer from the options given below : Includes table2022 · MCQ
  • Transition metal complex with highest value of crystal field splitting (Δ 0) will be :2022 · MCQ
  • Consider the following metal complexes : [Co(NH3​)6​]3+[CoCl(NH3​)5​]2+[Co(CN)6​]3−[Co(NH3​)5​(H2​O)]3+…2022 · Numerical