Sign in
12thPass logo
New chatPYQ LibraryDoubtsRank report
Sign in to see Recents

Your guest activity stays on this device

Sign in to save progress →
Sign in

Coordination Compounds question

2020 · 7 Jan · Shift 1 · Q14
Guest · filters and generic practice availableBrowsing as a guest · PYQ filters and generic practice are available. Sign in only for personalised features and saved progress.
  1. PYQ Library
  2. /JEE Main
  3. /Chemistry
  4. /Coordination Compounds
  5. /2020 · 7 Jan · Shift 1 · Q14

Coordination Compounds question

2020 · 7 Jan · Shift 1 · Q14

JEE MainChemistryCoordination CompoundsMCQ+4 / −1
The IUPAC name of complex [Pt(NH3)2Cl(NH2CH3)]Cl[Pt(NH_3)_2Cl(NH_2CH_3)]Cl[Pt(NH3​)2​Cl(NH2​CH3​)]Cl is:
  1. A
    Diamminechlorido (methanamine) platinum(II)chloride.
  2. B
    Biasmmine (methanamine)chlorido platinum(II)chloride.
  3. C
    Diamminechlorido (amminomethane) platinum(II) chloride.
  4. D
    Diammine (methanamine) chlorido platinum(II)Chloride.
View written solutionFree

Correct answer: A

  1. Write the complex clearly

    The compound is: [Pt(NH3)2Cl(NH2CH3)]Cl[Pt(NH_3)_2Cl(NH_2CH_3)]Cl[Pt(NH3​)2​Cl(NH2​CH3​)]Cl

    This contains:

    • Complex cation: [Pt(NH3)2Cl(NH2CH3)]+[Pt(NH_3)_2Cl(NH_2CH_3)]^+[Pt(NH3​)2​Cl(NH2​CH3​)]+
    • Counter anion: Cl−Cl^-Cl−
  2. Identify the ligands inside the coordination sphere

    Inside the bracket, the ligands are:

    • 222 molecules of NH3NH_3NH3​ = ammine
    • 111 ligand Cl−Cl^-Cl− = chlorido
    • 111 ligand NH2CH3NH_2CH_3NH2​CH3​ = methylamine, IUPAC ligand name = methanamine
  3. Find the oxidation state of Pt

    Let oxidation state of Pt be xxx.

    In the complex:

    • NH3NH_3NH3​ is neutral
    • NH2CH3NH_2CH_3NH2​CH3​ is neutral
    • Cl−Cl^-Cl− is −1-1−1
    • Overall charge on complex ion is +1+1+1

    So, x+0+0−1=+1x + 0 + 0 - 1 = +1x+0+0−1=+1 x=+2x = +2x=+2

    Hence, the metal is platinum(II).

  4. Arrange ligand names in alphabetical order

    Ligands are named alphabetically, ignoring multiplicative prefixes like di-, tri-, etc.

    Ligand names:

    • ammine
    • chlorido
    • methanamine

    Alphabetical order:

    • ammine
    • chlorido
    • methanamine

    Since there are two ammine ligands, it becomes diammine.

  5. Name the cation and then the anion

    So the complex cation is named: diamminechlorido(methanamine)platinum(II)\text{diamminechlorido(methanamine)platinum(II)}diamminechlorido(methanamine)platinum(II)

    Since there is one chloride ion outside the coordination sphere, the full name becomes: diamminechlorido(methanamine)platinum(II) chloride\text{diamminechlorido(methanamine)platinum(II) chloride}diamminechlorido(methanamine)platinum(II) chloride

  6. Check options

    • A: Diamminechlorido (methanamine) platinum(II)chloride. ✅ Correct in substance.
    • B: Biasmmine (methanamine)chlorido platinum(II)chloride. ❌ Wrong prefix/spelling/order.
    • C: Diamminechlorido (amminomethane) platinum(II) chloride. ❌ Wrong ligand name.
    • D: Diammine (methanamine) chlorido platinum(II)Chloride. ❌ Ligand order incorrect.
  7. Final answer

    The correct IUPAC name is: Diamminechlorido(methanamine)platinum(II) chloride\boxed{\text{Diamminechlorido(methanamine)platinum(II) chloride}}Diamminechlorido(methanamine)platinum(II) chloride​

    Hence, Option A is correct.

PreviousNext

More from Coordination Compounds

  • The theory that can completely/properly explain the nature of bonding in [Ni(Co)4​] is :2020 · MCQ
  • The number of possible optical isomers for the complexes MA2B2 with sp3 and dsp2 hydridized metal atom. respectively, is : Note : A and B are unidentate netural and unidentate monoanionic ligands, respectively.2020 · MCQ
  • Among the statements(a)-(d) the incorrect ones are : (a) Octahedral CO(III) complexes with strong fields ligands have very high magnetic moments. (b) When Δ 0 < P, the d-electron configuration of Co(III) in an octahedral complex…2020 · MCQ
  • The complex that can show fac- and mer-isomers is :2020 · MCQ
  • The correct order of the calculated spin-only magnetic moments of complexs (A) to (D) is: (A) Ni(CO)4​ (B) [Ni(H2​O)6​]Cl2​ (C) Na2​[Ni(CN)4​] (D) PdCl2​(PPh3​)2​2020 · MCQ
  • Among (a) – (d) the complexes that can display geometrical isomerism are : (a) [Pt(NH3​)3​Cl]+ (b) [Pt(NH3​)Cl5​]– (c) [Pt(NH3​)2​Cl(NO2​)] (d) [Pt(NH3​)4​ClBr]2+2020 · MCQ
  • Complexes (ML5​) of metals Ni and Fe have ideal square pyramidal and trigonal bipyramidal grometries, respectively. The sum of the 90°, 120° and 180° L-M-L angles in the two complexes is ​.2020 · Numerical
  • Complex X of composition Cr(H2​O)6​Cln has a spin only magnetic moment of 3.83 BM. It reacts with AgNO3​ and shows geometrical isomerism. The IUPAC nomenclature of X is :2020 · MCQ