- AWemer's theory
- BValence bond theory
- CCrystal field theory
- DMolecular orbital theory
View written solutionFree
Correct answer: D
-
Identify the complex and the bonding issue
The complex given is most likely nickel tetracarbonyl, written as .
We are asked which theory can completely/properly explain the nature of bonding in this complex.
-
Why this is a special case
In , the ligand is not just a simple donor ligand. It shows:
- -donation from the lone pair on carbon to nickel
- -back bonding from filled metal orbitals to empty orbitals of
So the bonding is synergic and involves both ligand-to-metal and metal-to-ligand interactions.
-
Check each theory
A. Werner's theory
Werner's theory explains:
- primary and secondary valencies
- coordination number
- basic formulation of complexes
But it does not explain orbital overlap, -bonding, or -back bonding.
Hence, A is incorrect.
B. Valence Bond Theory (VBT)
VBT can explain:
- hybridisation
- geometry
- whether orbitals are paired/unpaired in a basic way
For , VBT can describe hybridisation and tetrahedral geometry.
However, it cannot properly explain the full nature of bonding, especially the important -back bonding in metal carbonyls.
Hence, B is incorrect.
C. Crystal Field Theory (CFT)
CFT mainly treats ligands as point charges/point dipoles and explains:
- splitting of -orbitals
- magnetic behaviour
- colour in many complexes
But for metal carbonyls, where covalent interactions and back bonding are crucial, CFT is inadequate.
Hence, C is incorrect.
D. Molecular Orbital Theory (MOT)
MOT explains bonding using orbital interactions between metal and ligands.
In , MOT can properly account for:
- donation from to
- back donation from to
- the overall covalent nature and stability of the complex
Therefore, MOT completely/properly explains the bonding in .
Hence, D is correct.
-
Final answer
The correct option is:
-
Comparison with stored correct answer
Stored correct answer: D
Our derived answer: D
So they agree.
More from Coordination Compounds
- The number of possible optical isomers for the complexes MA2B2 with sp3 and dsp2 hydridized metal atom. respectively, is : Note : A and B are unidentate netural and unidentate monoanionic ligands, respectively.2020 · MCQ
- Among the statements(a)-(d) the incorrect ones are : (a) Octahedral CO(III) complexes with strong fields ligands have very high magnetic moments. (b) When 0 < P, the d-electron configuration of Co(III) in an octahedral complex…2020 · MCQ
- The complex that can show fac- and mer-isomers is :2020 · MCQ
- The correct order of the calculated spin-only magnetic moments of complexs (A) to (D) is: (A) (B) (C) (D) 2020 · MCQ
- Among (a) – (d) the complexes that can display geometrical isomerism are : (a) (b) (c) (d) 2020 · MCQ
- Complexes () of metals Ni and Fe have ideal square pyramidal and trigonal bipyramidal grometries, respectively. The sum of the 90°, 120° and 180° L-M-L angles in the two complexes is .2020 · Numerical
- Complex X of composition has a spin only magnetic moment of 3.83 BM. It reacts with and shows geometrical isomerism. The IUPAC nomenclature of X is :2020 · MCQ
- has n number of geometrical isomers. Then, the spin-only magnetic moment and crystal field stabilisation energy [CFSE] of , respectively, are: [Note : Ignore the pairing energy]2020 · MCQ