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Coordination Compounds question

2003 · Shift 0 · Q51
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Coordination Compounds question

2003 · Shift 0 · Q51

JEE MainChemistryCoordination CompoundsMCQ+4 / −1
In the coordination compound, K4[Ni(CN)4]K_4[Ni(CN)_4]K4​[Ni(CN)4​], the oxidation state of nickel is :
  1. A
    0
  2. B
    +1
  3. C
    +2
  4. D
    -1
View written solutionFree

Correct answer: A

  1. Write the compound and identify ionic parts

    The compound is K4[Ni(CN)4]K_4[Ni(CN)_4]K4​[Ni(CN)4​]

    Since potassium is an alkali metal, each KKK has oxidation state +1+1+1.

  2. Find the charge on the complex ion

    There are 444 potassium ions: 4×(+1)=+44 \times (+1) = +44×(+1)=+4

    Because the whole compound is neutral, the complex ion must have charge −4-4−4: [Ni(CN)4]4−[Ni(CN)_4]^{4-}[Ni(CN)4​]4−

  3. Assign oxidation state to ligands

    Cyanide, CN−CN^-CN−, is a monodentate ligand with charge −1-1−1.

    For 444 cyanide ligands: 4×(−1)=−44 \times (-1) = -44×(−1)=−4

  4. Let the oxidation state of Ni be xxx

    Then for the complex ion: x+4(−1)=−4x + 4(-1) = -4x+4(−1)=−4 x−4=−4x - 4 = -4x−4=−4 x=0x = 0x=0

  5. Evaluate the options

    • A: 000 ✅
    • B: +1+1+1 ❌
    • C: +2+2+2 ❌
    • D: −1-1−1 ❌
  6. Final answer

    The oxidation state of nickel is: 0\boxed{0}0​

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