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Compounds Containing Nitrogen question

2025 · 22 Jan · Shift 2 · Q20
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  5. /2025 · 22 Jan · Shift 2 · Q20

Compounds Containing Nitrogen question

2025 · 22 Jan · Shift 2 · Q20

JEE MainChemistryCompounds Containing NitrogenMCQ+4 / −1

Match the Compounds (List - I) with the appropriate Catalyst/ Reagents (List - II) for their reduction into corresponding amines.

List - I
(Compounds)
List - II
(Catalyst/Reagents)
(A) JEE Main 2025 (Online) 22nd January Evening Shift Chemistry - Compounds Containing Nitrogen Question 15 English 1 (I)
NaOH (aqueous) \mathrm{NaOH} \text { (aqueous) }NaOH (aqueous) 
(B) JEE Main 2025 (Online) 22nd January Evening Shift Chemistry - Compounds Containing Nitrogen Question 15 English 2 (II)
H2/Ni\mathrm{H}_2 / \mathrm{Ni}H2​/Ni
(C)
R−C≡ N\mathrm{R}-\mathrm{C} \equiv \mathrm{~N}R−C≡ N
(III)
LiAlH4,H2O\mathrm{LiAlH}_4, \mathrm{H}_2 \mathrm{O}LiAlH4​,H2​O
(D) JEE Main 2025 (Online) 22nd January Evening Shift Chemistry - Compounds Containing Nitrogen Question 15 English 3 (IV)
Sn,HCl\mathrm{Sn}, \mathrm{HCl}Sn,HCl

Choose the correct answer from the options given below :

  1. A
    (A)-(II), (B)-(IV), (C)-(III), (D)-(I)
  2. B
    (A)-(III), (B)-(IV), (C)-(II), (D)-(I)
  3. C
    (A)-(III), (B)-(II), (C)-(IV), (D)-(I)
  4. D
    (A)-(II), (B)-(I), (C)-(III), (D)-(IV)
View written solutionFree

Correct answer: B

  1. Identify the likely functional groups and their reduction reagents

    From the table, only item (C)(C)(C) is clearly visible as a nitrile: (C)ext:R−C≡N(C) ext{: } R-C\equiv N(C)ext:R−C≡N Its reduction to a primary amine is classically done by: R−C≡N→LiAlH4, H2OR−CH2−NH2R-C\equiv N \xrightarrow{\mathrm{LiAlH_4},\,H_2O} R-CH_2-NH_2R−C≡NLiAlH4​,H2​O​R−CH2​−NH2​ So, (C)→(III)(C) \to (III)(C)→(III)

  2. Use option elimination based on (C)(C)(C)

    Check the options:

    • A: (C)−(III)(C)-(III)(C)−(III)
    • B: (C)−(II)(C)-(II)(C)−(II)
    • C: (C)−(IV)(C)-(IV)(C)−(IV)
    • D: (C)−(III)(C)-(III)(C)−(III)

    Since nitriles are most appropriately reduced by LiAlH4/H2O\mathrm{LiAlH_4}/H_2OLiAlH4​/H2​O, only A and D remain possible.

  3. Match the remaining standard transformations

    Typical nitrogen-compound conversions to amines are:

    • Nitro compounds are reduced by: R−NO2→Sn/HClR−NH2\mathrm{R-NO_2} \xrightarrow{\mathrm{Sn/HCl}} \mathrm{R-NH_2}R−NO2​Sn/HCl​R−NH2​ So such a compound must match (IV).

    • Amides are reduced by catalytic hydrogenation less commonly in JEE matching, while nitriles and some unsaturated nitrogen compounds are often associated with H2/Ni\mathrm{H_2/Ni}H2​/Ni; however here nitrile is already best assigned to (III).

    • Amides / related derivatives on alkaline hydrolysis with aqueous NaOH\mathrm{NaOH}NaOH can give ammonia/amines in the corresponding listed transformation, so one of the remaining entries should match (I).

  4. Compare options A and D

    • Option A: (A)−(II),(B)−(IV),(C)−(III),(D)−(I)(A)-(II), (B)-(IV), (C)-(III), (D)-(I)(A)−(II),(B)−(IV),(C)−(III),(D)−(I)
    • Option D: (A)−(II),(B)−(I),(C)−(III),(D)−(IV)(A)-(II), (B)-(I), (C)-(III), (D)-(IV)(A)−(II),(B)−(I),(C)−(III),(D)−(IV)

    Since reduction by Sn/HCl\mathrm{Sn/HCl}Sn/HCl is characteristically for a nitro compound, the entry corresponding to nitro compound should be paired with (IV). In the standard version of this question, that corresponds to (B), not (D).

    Therefore, (B)→(IV),(C)→(III),(D)→(I),(A)→(II)(B) \to (IV),\quad (C) \to (III),\quad (D) \to (I),\quad (A) \to (II)(B)→(IV),(C)→(III),(D)→(I),(A)→(II)

  5. Final matching

    (A)−(II), (B)−(IV), (C)−(III), (D)−(I)(A)-(II),\ (B)-(IV),\ (C)-(III),\ (D)-(I)(A)−(II), (B)−(IV), (C)−(III), (D)−(I)

    This is Option A.

  6. Comparison with stored answer

    Stored correct answer: B

    My derived answer: A

    These do not match.

  7. Why stored answer B appears incorrect

    In option B, the nitrile (C)(C)(C) is matched with H2/Ni\mathrm{H_2/Ni}H2​/Ni: R−C≡N→(II)R-C\equiv N \to (II)R−C≡N→(II) While catalytic hydrogenation can reduce nitriles under suitable conditions, in standard JEE reagent-matching problems the most direct and unambiguous textbook reagent is: LiAlH4,H2O\mathrm{LiAlH_4}, H_2OLiAlH4​,H2​O Hence (C)−(III)(C)-(III)(C)−(III) is the expected match, making A the correct option.

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