1. Identify the reaction sequence

Aniline undergoes diazotisation to form benzenediazonium chloride, which then couples with phenol to give an azo dye:

$\text{C}_6\text{H}_5\text{NH}_2 \xrightarrow[\text{NaNO}_2]{\text{HCl},\,0-5^\circ C} \text{C}_6\text{H}_5\text{N}_2^+\text{Cl}^-$

Then,

$\text{C}_6\text{H}_5\text{N}_2^+\text{Cl}^- + \text{C}_6\text{H}_5\text{OH} \rightarrow \text{p-hydroxyazobenzene} + \text{HCl}$

The orange dye formed is p-hydroxyazobenzene.

2. Find moles of aniline

Molar mass of aniline, $\text{C}_6\text{H}_7\text{N}$:

$6\times 12 + 7\times 1 + 14 = 72 + 7 + 14 = 93\ \text{g mol}^{-1}$

Given mass of aniline = $9.3\ \text{g}$

$\text{Moles of aniline} = \frac{9.3}{93} = 0.1\ \text{mol}$

3. Use stoichiometry

Diazotisation is a $1:1$ conversion, and azo coupling with phenol also gives $1:1$ formation of dye.

So,

$\text{Moles of dye formed} = 0.1\ \text{mol}$

4. Find molar mass of the dye

The dye is $p$-hydroxyazobenzene with formula:

$\text{C}_{12}\text{H}_{10}\text{N}_2\text{O}$

Molar mass:

$12\times 12 + 10\times 1 + 2\times 14 + 16 = 144 + 10 + 28 + 16 = 198\ \text{g mol}^{-1}$

5. Calculate mass of dye formed

$\text{Mass of dye} = 0.1 \times 198 = 19.8\ \text{g}$

Nearest integer:

$\boxed{20}$

6. Compare with stored answer

Stored correct answer = $20$

Our derived answer = $20$

So they agree.