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Compounds Containing Nitrogen question

2024 · 8 Apr · Shift 1 · Q21
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Compounds Containing Nitrogen question

2024 · 8 Apr · Shift 1 · Q21

JEE MainChemistryCompounds Containing NitrogenNumerical+4 / −1
If 279 g279 \mathrm{~g}279 g of aniline is reacted with one equivalent of benzenediazonium chloride, the maximum amount of aniline yellow formed will be ‾\underline{\hspace{2cm}}​ g. (nearest integer) (consider complete conversion).
Numerical answer
View written solutionFree

Correct answer: 591

  1. Reaction involved

Aniline couples with benzenediazonium chloride to form aniline yellow (an azo compound):

\ceC6H5N2+Cl−+C6H5NH2−>C6H5−N=N−C6H4−NH2+HCl\ce{C6H5N2+Cl- + C6H5NH2 -> C6H5-N=N-C6H4-NH2 + HCl}\ceC6H5N2+Cl−+C6H5NH2−>C6H5−N=N−C6H4−NH2+HCl

Thus, the stoichiometric ratio is:

1 mol aniline:1 mol benzenediazonium chloride:1 mol aniline yellow1\text{ mol aniline} : 1\text{ mol benzenediazonium chloride} : 1\text{ mol aniline yellow}1 mol aniline:1 mol benzenediazonium chloride:1 mol aniline yellow
  1. Moles of aniline given

Molar mass of aniline, \ceC6H5NH2\ce{C6H5NH2}\ceC6H5NH2:

6(12)+7(1)+14=72+7+14=93 g mol−16(12) + 7(1) + 14 = 72 + 7 + 14 = 93\,\text{g mol}^{-1}6(12)+7(1)+14=72+7+14=93g mol−1

Given mass = 279 g279\,\text{g}279g

moles of aniline=27993=3 mol\text{moles of aniline} = \frac{279}{93} = 3\,\text{mol}moles of aniline=93279​=3mol
  1. Effect of "one equivalent" of benzenediazonium chloride

"One equivalent" means equimolar amount relative to aniline, so benzenediazonium chloride also has:

3 mol3\,\text{mol}3mol

Since the reaction is 1:11:11:1, maximum moles of aniline yellow formed:

3 mol3\,\text{mol}3mol
  1. Molar mass of aniline yellow

Aniline yellow structure: \ceC6H5−N=N−C6H4−NH2\ce{C6H5-N=N-C6H4-NH2}\ceC6H5−N=N−C6H4−NH2

Molecular formula:

\ceC12H11N3\ce{C12H11N3}\ceC12H11N3

Molar mass:

12(12)+11(1)+3(14)=144+11+42=197 g mol−112(12) + 11(1) + 3(14) = 144 + 11 + 42 = 197\,\text{g mol}^{-1}12(12)+11(1)+3(14)=144+11+42=197g mol−1
  1. Mass of aniline yellow formed
mass=3×197=591 g\text{mass} = 3 \times 197 = 591\,\text{g}mass=3×197=591g
  1. Final answer

The maximum amount of aniline yellow formed is:

591 g\boxed{591\,\text{g}}591g​
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