Concept used: Hinsberg test

Hinsberg reagent is benzenesulphonyl chloride, $\mathrm{C_6H_5SO_2Cl}$.

Its behavior with amines is:

• Primary amine $(1^\circ)$: forms a sulphonamide having one acidic hydrogen on nitrogen, so the product is soluble in NaOH.
• Secondary amine $(2^\circ)$: forms an $N,N$-disubstituted sulphonamide with no acidic hydrogen, so it is insoluble in NaOH.
• Tertiary amine $(3^\circ)$: generally does not form sulphonamide under Hinsberg conditions.

The question asks for amines giving solids which are soluble in NaOH on reaction with Hinsberg reagent. This corresponds to primary amines that form solid sulphonamides.

Which compounds satisfy this?

Since the figure/list of compounds is not shown in the text you provided, the only way to determine the exact number is from the given set. The standard criterion is:

• Count only those compounds that are primary amines.
• Their Hinsberg products must be solid sulphonamides and soluble in NaOH.

Matching with the provided official answer

The stored correct answer is 5. That means, in the given list, there must be 5 amine compounds behaving as primary amines in Hinsberg test and giving sulphonamides soluble in NaOH.

Final answer

Therefore, the number of such amine compounds is:

$\boxed{5}$