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Chemical Kinetics and Nuclear Chemistry question

2024 · 31 Jan · Shift 1 · Q11
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Chemical Kinetics and Nuclear Chemistry question

2024 · 31 Jan · Shift 1 · Q11

JEE MainChemistryChemical Kinetics and Nuclear ChemistryMCQ+4 / −1
Integrated rate law equation for a first order gas phase reaction is given by (where Pi\mathrm{P}_{\mathrm{i}}Pi​ is initial pressure and Pt\mathrm{P}_{\mathrm{t}}Pt​ is total pressure at time ttt)
  1. A
    k=2.303t×log⁡Pi(2Pi−Pt)k=\frac{2.303}{t} \times \log \frac{P_i}{\left(2 P_i-P_t\right)}k=t2.303​×log(2Pi​−Pt​)Pi​​
  2. B
    k=2.303t×log⁡(2Pi−Pt)Pi\mathrm{k}=\frac{2.303}{\mathrm{t}} \times \log \frac{\left(2 \mathrm{P}_{\mathrm{i}}-\mathrm{P}_{\mathrm{t}}\right)}{\mathrm{P}_{\mathrm{i}}}k=t2.303​×logPi​(2Pi​−Pt​)​
  3. C
    k=2.303t×Pi(2Pi−Pt)k=\frac{2.303}{t} \times \frac{P_i}{\left(2 P_i-P_t\right)}k=t2.303​×(2Pi​−Pt​)Pi​​
  4. D
    k=2.303t×log⁡2Pi(2Pi−Pt)\mathrm{k}=\frac{2.303}{\mathrm{t}} \times \log \frac{2 \mathrm{P}_{\mathrm{i}}}{\left(2 \mathrm{P}_{\mathrm{i}}-\mathrm{P}_{\mathrm{t}}\right)}k=t2.303​×log(2Pi​−Pt​)2Pi​​
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