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Chemical Kinetics and Nuclear Chemistry question

2021 · 31 Aug · Shift 2 · Q18
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Chemical Kinetics and Nuclear Chemistry question

2021 · 31 Aug · Shift 2 · Q18

JEE MainChemistryChemical Kinetics and Nuclear ChemistryNumerical+4 / −1
For the reaction A →\to→ B, the rate constant k(in s −-− 1) is given by log⁡10k=20.35−(2.47×103)T{\log _{10}}k = 20.35 - {{(2.47 \times {{10}^3})} \over T}log10​k=20.35−T(2.47×103)​ The energy of activation in kJ mol −-− 1 is ‾\underline{\hspace{2cm}}​. (Nearest integer) [Given : R = 8.314 J K −-− 1 mol −-− 1]
Numerical answer
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