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Chemical Kinetics and Nuclear Chemistry question

2021 · 24 Feb · Shift 2 · Q20
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Chemical Kinetics and Nuclear Chemistry question

2021 · 24 Feb · Shift 2 · Q20

JEE MainChemistryChemical Kinetics and Nuclear ChemistryNumerical+4 / −1
Sucrose hydrolyses in acid solution into glucose and fructose following first order rate law with a half-life of 3.33 h at 25 ∘^\circ∘ C. After 9 h, the fraction of sucrose remaining is f. The value of log⁡10(1f){\log _{10}}\left( {{1 \over f}} \right)log10​(f1​) is ‾\underline{\hspace{2cm}}​×\times× 10 −-− 2. (Rounded off to the nearest integer) [Assume : ln 10 = 2.303, ln 2 = 0.693]
Numerical answer
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