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Chemical Kinetics and Nuclear Chemistry question

2021 · 26 Feb · Shift 2 · Q18
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Chemical Kinetics and Nuclear Chemistry question

2021 · 26 Feb · Shift 2 · Q18

JEE MainChemistryChemical Kinetics and Nuclear ChemistryNumerical+4 / −1
If the activation energy of a reaction is 80.9 kJ mol −-− 1, the fraction of molecules at 700 K, having enough energy to react to form products is e −-− x. The value of x is ‾\underline{\hspace{2cm}}​. (Rounded off to the nearest integer) [Use R = 8.31 J K −-− 1 mol −-− 1]
Numerical answer
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