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Chemical Kinetics and Nuclear Chemistry question

2021 · 25 Jul · Shift 2 · Q20
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Chemical Kinetics and Nuclear Chemistry question

2021 · 25 Jul · Shift 2 · Q20

JEE MainChemistryChemical Kinetics and Nuclear ChemistryNumerical+4 / −1
For a chemical reaction A →\to→ B, it was found that concentration of B is increased by 0.2 mol L −-− in 30 min. The average rate of the reaction is ‾\underline{\hspace{2cm}}​×\times× 10 −-− 1 mol L −-− 1 h −-− 1. (in nearest integer)
Numerical answer
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Correct answer: 4

  1. For the reaction A→BA \to BA→B the stoichiometric coefficients of AAA and BBB are both 1.

  2. The average rate of reaction can be written in terms of product formation as Average rate=Δ[B]Δt\text{Average rate} = \frac{\Delta [B]}{\Delta t}Average rate=ΔtΔ[B]​

  3. Given:

    • Increase in concentration of BBB: Δ[B]=0.2 mol L−1\Delta [B] = 0.2\,\text{mol L}^{-1}Δ[B]=0.2mol L−1
    • Time interval: Δt=30 min=0.5 h\Delta t = 30\,\text{min} = 0.5\,\text{h}Δt=30min=0.5h
  4. Therefore, Average rate=0.20.5=0.4 mol L−1h−1\text{Average rate} = \frac{0.2}{0.5} = 0.4\,\text{mol L}^{-1}\text{h}^{-1}Average rate=0.50.2​=0.4mol L−1h−1

  5. The question asks to write this as ‾×10−1 mol L−1h−1\underline{\hspace{2cm}} \times 10^{-1}\,\text{mol L}^{-1}\text{h}^{-1}​×10−1mol L−1h−1

    Since 0.4=4×10−10.4 = 4 \times 10^{-1}0.4=4×10−1

  6. Hence, the required integer is 4\boxed{4}4​

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