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Chemical Equilibrium question

2023 · 29 Jan · Shift 1 · Q19
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  5. /2023 · 29 Jan · Shift 1 · Q19

Chemical Equilibrium question

2023 · 29 Jan · Shift 1 · Q19

JEE MainChemistryChemical EquilibriumNumerical+4 / −1
Consider the following reaction approaching equilibrium at 27 ∘^\circ∘ C and 1 atm pressure A+B\mathrm{A+B}A+B ⇌kr=102kf=103\mathrel{\mathop{\kern0pt\rightleftharpoons} \limits_{{k_r} = {{10}^2}}^{{k_f} = {{10}^3}}}kr​=102⇌kf​=103​ C+D\mathrm{C+D}C+D The standard Gibb's energy change (ΔrGθ)\mathrm{(\Delta_r G^\theta)}(Δr​Gθ) at 27 ∘^\circ∘ C is (−-−) ‾\underline{\hspace{2cm}}​ kJ mol −1^{-1}−1(Nearest integer). (Given : R=8.3 J K−1 mol−1\mathrm{R=8.3~J~K^{-1}~mol^{-1}}R=8.3 J K−1 mol−1 and ln⁡10=2.3\mathrm{\ln 10=2.3}ln10=2.3)
Numerical answer
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