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Chemical Equilibrium question

2022 · 25 Jun · Shift 1 · Q19
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Chemical Equilibrium question

2022 · 25 Jun · Shift 1 · Q19

JEE MainChemistryChemical EquilibriumNumerical+4 / −1
The standard free energy change (Δ\DeltaΔ G ∘^\circ∘) for 50% dissociation of N2O4N_2O_4N2​O4​ into NO2NO_2NO2​ at 27 ∘^\circ∘ C and 1 atm pressure is −-− x J mol −-− 1. The value of x is ‾\underline{\hspace{2cm}}​. (Nearest Integer) [Given : R = 8.31 J K −-− 1 mol −-− 1, log 1.33 = 0.1239 ln 10 = 2.3]
Numerical answer
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