1. Count the valence electrons around Xe

   Xenon has 8 valence electrons.

   In $XeOF_4$, xenon is bonded to:

   • one oxygen atom
   • four fluorine atoms

2. Count the number of sigma bonds around Xe

   Structure of $XeOF_4$:

   • $Xe=O$ contributes one sigma bond and one pi bond
   • four $Xe-F$ bonds contribute four sigma bonds

   So, total number of sigma bonds around Xe is: $1 + 4 = 5$

3. Determine lone pairs on Xe

   Xenon starts with 8 valence electrons. After forming 5 sigma bonds, one lone pair remains on Xe.

   More formally, steric number is determined by: $\text{Steric number} = \text{sigma bonds} + \text{lone pairs}$

   For $XeOF_4$, known arrangement is octahedral electron pair geometry with: $5\ \text{bond pairs} + 1\ \text{lone pair} = 6$

   Hence Xe has 1 lone pair.

4. Determine hybridisation

   Since steric number $=6$, the hybridisation is: $sp^3d^2$

5. Match with options

   • A: $sp^3d$ and 2 ❌
   • B: $sp^3d^2$ and 2 ❌
   • C: $sp^3d$ and 1 ❌
   • D: $sp^3d^2$ and 1 ✅

Therefore, the correct answer is D.