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Basics of Organic Chemistry question

2025 · 22 Jan · Shift 1 · Q12
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Basics of Organic Chemistry question

2025 · 22 Jan · Shift 1 · Q12

JEE MainChemistryBasics of Organic ChemistryMCQ+4 / −1
The incorrect statements regarding geometrical isomerism are : (A) Propene shows geometrical isomerism. (B) Trans isomer has identical atoms/groups on the opposite sides of the double bond. (C) Cis-but-2-ene has higher dipole moment than trans-but-2-ene. (D) 2-methylbut-2-ene shows two geometrical isomers. (E) Trans-isomer has lower melting point than cis isomer. Choose the correct answer from the options given below :
  1. A
    (A) and (E) Only
  2. B
    (A), (D) and (E) Only
  3. C
    (C), (D) and (E) Only
  4. D
    (B) and (C) Only
View written solutionFree

Correct answer: B

  1. Condition for geometrical isomerism
    A compound shows geometrical isomerism about a double bond only if each carbon of the double bond has two different groups attached.

  1. Check statement (A): Propene shows geometrical isomerism
    Propene is CH3−CH=CH2\mathrm{CH_3-CH=CH_2}CH3​−CH=CH2​.
  • Left double-bond carbon has groups: CH3\mathrm{CH_3}CH3​ and H\mathrm{H}H
  • Right double-bond carbon has groups: H\mathrm{H}H and H\mathrm{H}H

Since one carbon has two identical groups (H,H\mathrm{H,H}H,H), geometrical isomerism is not possible.

So, (A) is incorrect.


  1. Check statement (B): Trans isomer has identical atoms/groups on the opposite sides of the double bond
    This is the definition of trans isomer (for simple cis-trans systems): identical or similar reference groups are on opposite sides.

So, (B) is correct.


  1. Check statement (C): Cis-but-2-ene has higher dipole moment than trans-but-2-ene
    In cis-but-2-ene, bond dipoles reinforce each other more, so net dipole moment is higher.
    In trans-but-2-ene, the dipoles cancel to a large extent, so dipole moment is lower.

So, (C) is correct.


  1. Check statement (D): 2-methylbut-2-ene shows two geometrical isomers
    Structure of 2-methylbut-2-ene: CH3−C(CH3)=CH−CH3\mathrm{CH_3-C(CH_3)=CH-CH_3}CH3​−C(CH3​)=CH−CH3​

At the left double-bond carbon, the two groups are:

  • CH3\mathrm{CH_3}CH3​
  • CH3\mathrm{CH_3}CH3​

These are identical. Hence geometrical isomerism is not possible.

So, (D) is incorrect.


  1. Check statement (E): Trans-isomer has lower melting point than cis isomer
    Generally:
  • cis isomer has higher dipole moment and often higher boiling point
  • trans isomer is usually more symmetrical, packs better in crystal lattice, and often has higher melting point than cis isomer

Therefore the statement "trans-isomer has lower melting point than cis isomer" is generally incorrect.

So, (E) is incorrect.


  1. List of incorrect statements
    Incorrect statements are: (A),(D),(E)\boxed{(A), (D), (E)}(A),(D),(E)​

Thus the correct option is: B\boxed{\text{B}}B​


  1. Comparison with stored answer
    Stored correct answer = B
    Derived answer = B
    So, they agree.
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