
- A1-Ethylcyclopent-2-en-3-ol
- B4-Ethylcyclopent-2-en-1-ol
- C1-Ethyl-3-hydroxycyclopent-2-ene
- D4-Ethyl-1-hydroxycyclopent-2-ene
View written solutionFree
Correct answer: B
-
Identify the principal functional group
The compound contains:
- an alcohol group,
- a double bond
- an ethyl substituent
In IUPAC nomenclature, the alcohol has higher priority than the double bond, so the parent name must use the suffix -ol.
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Choose the parent ring and numbering
The parent ring is cyclopentene/cyclopentanol framework, i.e. a five-membered ring.
Since is the principal functional group, numbering must start from the carbon bearing the group.
So the carbon with gets locant 1.
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Assign positions to the double bond and substituent
After giving locant 1, number the ring in the direction that gives the double bond the lowest possible locant.
This gives:
- at carbon
- double bond at carbon so parent becomes cyclopent-2-en-1-ol
- ethyl substituent at carbon
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Write the complete name
Therefore, the correct IUPAC name is:
-
Check the options
- A: -Ethylcyclopent--en--ol incorrect, because the group should get locant .
- B: -Ethylcyclopent--en--ol correct.
- C: -Ethyl--hydroxycyclopent--ene incorrect, because alcohol should be written as suffix -ol, not prefix hydroxy, when it is the principal group.
- D: -Ethyl--hydroxycyclopent--ene incorrect for the same reason.
-
Comparison with stored correct answer
My derived answer is B, which matches the stored correct answer.
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