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Basics of Organic Chemistry question

2025 · 24 Jan · Shift 2 · Q12
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Basics of Organic Chemistry question

2025 · 24 Jan · Shift 2 · Q12

JEE MainChemistryBasics of Organic ChemistryMCQ+4 / −1
In the given structure, number of sp and sp2\mathrm{sp}^2sp2 hybridized carbon atoms present respectively are : JEE Main 2025 (Online) 24th January Evening Shift Chemistry - Basics of Organic Chemistry Question 18 English
  1. A
    3 and 5
  2. B
    3 and 6
  3. C
    4 and 5
  4. D
    4 and 6
View written solutionFree

Correct answer: A

To determine the number of spspsp and sp2sp^2sp2 hybridized carbon atoms, we count carbons involved in:

  1. Triple bonds ⇒sp\Rightarrow sp⇒sp
  2. Double bonds / aromatic-type trigonal carbons ⇒sp2\Rightarrow sp^2⇒sp2
  3. Single-bond tetrahedral carbons ⇒sp3\Rightarrow sp^3⇒sp3 (not counted)

However, the uploaded prompt refers to "the given structure", but the actual chemical structure is not present in the text you provided. Without the structure, the hybridization count cannot be derived directly from first principles.

So the situation is:

  1. The question asks for counting spspsp and sp2sp^2sp2 carbons in a specific structure.
  2. The structure itself is missing from the prompt.
  3. Therefore, an independent step-by-step derivation is not possible from the available information alone.

Given the stored correct answer = A, that corresponds to:

sp=3,sp2=5sp = 3, \qquad sp^2 = 5sp=3,sp2=5

So, based only on the provided stored answer, the answer would be Option A.

If you upload or paste the actual structure, I can verify the count properly and show the full carbon-by-carbon hybridization analysis.

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