Match the LIST-I with LIST-II LIST-I LIST-II A. Carbocation I. Species that can supply a pair of electrons. B. C-Free radical II. Species that can receive a pair of electrons. C. Nucleophile III. sp 2 hybridized carbon with empty p-orbital. D. Electrophile IV. sp 2 /sp 3 hybridized carbon with one unpaired electron. Choose the correct answer from the options given below:

Basics of Organic Chemistry PYQ — JEE Main 2025 · 8 Apr · Shift 2 · Q3 with Solution

Match the LIST-I with LIST-II

LIST-I	LIST-II
A. Carbocation	I. Species that can supply a pair of electrons.
B. C-Free radical	II. Species that can receive a pair of electrons.
C. Nucleophile	III. sp² hybridized carbon with empty p-orbital.
D. Electrophile	IV. sp²/sp³ hybridized carbon with one unpaired electron.

Choose the correct answer from the options given below:

View written solutionFree

Correct answer: C

Identify each species/term in LIST-I
- A. Carbocation: A carbocation is a positively charged carbon species. The carbon is typically $sp^2$ hybridized and has an empty $p$ -orbital.
  
  So, A $\to$ III.
- B. C-Free radical: A carbon free radical has one unpaired electron. Such carbon is generally considered $sp^2$ or sometimes nearly $sp^3$ hybridized depending on structure.
  
  So, B $\to$ IV.
- C. Nucleophile: A nucleophile is an electron-rich species that donates a pair of electrons.
  
  So, C $\to$ I.
- D. Electrophile: An electrophile is an electron-deficient species that accepts/receives a pair of electrons.
  
  So, D $\to$ II.
Write the complete matching

$A\! -\! III, \quad B\! -\! IV, \quad C\! -\! I, \quad D\! -\! II$
Compare with the given options
- Option A: $A$ -IV, $B$ -II, $C$ -III, $D$ -I ❌
- Option B: $A$ -II, $B$ -III, $C$ -I, $D$ -IV ❌
- Option C: $A$ -III, $B$ -IV, $C$ -I, $D$ -II ✅
- Option D: $A$ -III, $B$ -IV, $C$ -II, $D$ -I ❌
Final answer

The correct option is C.

Match the LIST-I with LIST-II

LIST-I	LIST-II
A. Carbocation	I. Species that can supply a pair of electrons.
B. C-Free radical	II. Species that can receive a pair of electrons.
C. Nucleophile	III. sp² hybridized carbon with empty p-orbital.
D. Electrophile	IV. sp²/sp³ hybridized carbon with one unpaired electron.

Choose the correct answer from the options given below:

View written solutionFree

Correct answer: C

Identify each species/term in LIST-I
- A. Carbocation: A carbocation is a positively charged carbon species. The carbon is typically $sp^2$ hybridized and has an empty $p$ -orbital.
  
  So, A $\to$ III.
- B. C-Free radical: A carbon free radical has one unpaired electron. Such carbon is generally considered $sp^2$ or sometimes nearly $sp^3$ hybridized depending on structure.
  
  So, B $\to$ IV.
- C. Nucleophile: A nucleophile is an electron-rich species that donates a pair of electrons.
  
  So, C $\to$ I.
- D. Electrophile: An electrophile is an electron-deficient species that accepts/receives a pair of electrons.
  
  So, D $\to$ II.
Write the complete matching

$A\! -\! III, \quad B\! -\! IV, \quad C\! -\! I, \quad D\! -\! II$
Compare with the given options
- Option A: $A$ -IV, $B$ -II, $C$ -III, $D$ -I ❌
- Option B: $A$ -II, $B$ -III, $C$ -I, $D$ -IV ❌
- Option C: $A$ -III, $B$ -IV, $C$ -I, $D$ -II ✅
- Option D: $A$ -III, $B$ -IV, $C$ -II, $D$ -I ❌
Final answer

The correct option is C.