The question asks: Which compound will show geometrical isomerism?

However, the actual structures/options for A, B, C, D are missing in the prompt. Since geometrical isomerism depends entirely on the structure of the compound, it is not possible to determine the correct option without seeing those structures.

1. Condition for geometrical isomerism

A compound shows geometrical isomerism only when:

1. There is restricted rotation (commonly due to a double bond or a ring), and
2. Each doubly bonded carbon must have two different substituents.

For example, in an alkene: $\mathrm{R_1R_2C=CR_3R_4}$ Geometrical isomerism is possible only if: $R_1 \ne R_2 \quad \text{and} \quad R_3 \ne R_4$

If either carbon of the double bond has two identical groups, then geometrical isomerism is not possible.

2. Why the answer cannot be derived here

The options are shown as:

• A:
• B:
• C:
• D:

with no compounds/structures provided. Therefore, there is no way to test which one satisfies the above condition.

3. Comparison with stored answer

The stored correct answer is A, but since the actual option structures are absent, I cannot verify whether A is truly correct.

So, based on the information given, the problem is incomplete.