1. We need the bond-line formula of $\mathrm{HOCH(CN)_2}$.

2. First, interpret the condensed formula: $\mathrm{HOCH(CN)_2}$ This means one central carbon atom is attached to:

   • one $\mathrm{OH}$ group,
   • one $\mathrm{H}$ atom,
   • two $\mathrm{CN}$ groups.

3. So the expanded structure is: $\mathrm{NC-CH(OH)-CN}$ or equivalently, $\mathrm{HO-CH(CN)_2}$

4. Now identify what this looks like in bond-line form:

   • The central carbon is a carbon with four single bonds.
   • It is bonded to $\mathrm{OH}$, to $\mathrm{H}$, and to two nitrile groups $(-\mathrm{C\equiv N})$.
   • Thus the correct skeletal drawing must show a central carbon connected to two $\mathrm{C\equiv N}$ groups and one $\mathrm{OH}$.

5. Among the given options, the one corresponding to this arrangement is Option D.

Therefore, the correct answer is: $\boxed{\text{D}}$