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Basics of Organic Chemistry question

2022 · 28 Jul · Shift 1 · Q9
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Basics of Organic Chemistry question

2022 · 28 Jul · Shift 1 · Q9

JEE MainChemistryBasics of Organic ChemistryMCQ+4 / −1
Among the following marked proton of which compound shows lowest pKa\mathrm{pK}_{\mathrm{a}}pKa​ value?
  1. A
    JEE Main 2022 (Online) 28th July Morning Shift Chemistry - Basics of Organic Chemistry Question 117 English Option 1
  2. B
    JEE Main 2022 (Online) 28th July Morning Shift Chemistry - Basics of Organic Chemistry Question 117 English Option 2
  3. C
    JEE Main 2022 (Online) 28th July Morning Shift Chemistry - Basics of Organic Chemistry Question 117 English Option 3
  4. D
    JEE Main 2022 (Online) 28th July Morning Shift Chemistry - Basics of Organic Chemistry Question 117 English Option 4
View written solutionFree

Correct answer: C

The question asks: among the marked protons, which has the lowest pKa\mathrm{p}K_apKa​?

However, the structures/options A, B, C, D are missing in the prompt. Since pKa\mathrm{p}K_apKa​ depends completely on the specific compound and the marked proton, the problem cannot be solved from the given text alone.

Why the structures are necessary

For an acidic proton, the pKa\mathrm{p}K_apKa​ is determined by the stability of the conjugate base formed after deprotonation. Important factors include:

  1. Resonance stabilization of the conjugate base
  2. Inductive effects (−I-I−I groups lower pKa\mathrm{p}K_apKa​)
  3. Hybridization of the atom bearing negative charge
  4. Aromatic stabilization after deprotonation
  5. Electronegativity and neighboring functional groups

Without seeing the actual compounds, it is impossible to compare their acidities.

Conclusion

Because the options are not visible, I cannot independently derive whether A, B, C, or D is correct.

The stored correct answer is C, but there is not enough information to verify it from the problem statement provided.

If you upload or type the structures of options A, B, C, and D, I can solve it fully and verify the answer step-by-step.

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