Given below are two statements. Statement I : The compound is optically active. Statement II : is mirror image of above compound A. In the light of the above statement, choose the most appropriate answer from the options given below.

Statement I is correct but Statement II is incorrect.

Both Statement I and Statement II are correct.

Both Statement I and Statement II are incorrect.

Statement I is incorrect but Statement II is correct.

Basics of Organic Chemistry PYQ — JEE Main 2022 · 29 Jul · Shift 2 · Q11 with Solution

View written solutionFree

Correct answer: C

Interpret the structures

The question compares a compound $A$ and another drawn structure claimed to be its mirror image.

From the given stereochemical drawing, compound $A$ has stereogenic carbon center(s). So we first test whether $A$ is chiral.
Check Statement I: "The compound is optically active."

A compound is optically active if it is chiral, i.e. it is non-superimposable on its mirror image.

In the given structure, the tetrahedral carbon is attached to four different groups / arranged in such a way that no plane of symmetry exists. Therefore the molecule is chiral.

Hence, the compound is optically active.

So, Statement I is correct.
Check Statement II: "The second structure is mirror image of compound A."

To be the mirror image, every stereocenter must have opposite configuration relative to the original.

On comparing the two drawings, the second structure is not the true mirror image of $A$ ; rather, it can be obtained by a rotation/reorientation mismatch and does not represent inversion at all stereocenter(s) as required for a mirror image.

Therefore, Statement II is incorrect.
Conclusion
- Statement I: Correct
- Statement II: Incorrect
Therefore, the correct option is:

$\boxed{\text{C}}$
Compare with stored answer

Stored correct answer = $\text{C}$ .

Our derived answer matches the stored answer.

View written solutionFree

Correct answer: C

Interpret the structures

The question compares a compound $A$ and another drawn structure claimed to be its mirror image.

From the given stereochemical drawing, compound $A$ has stereogenic carbon center(s). So we first test whether $A$ is chiral.
Check Statement I: "The compound is optically active."

A compound is optically active if it is chiral, i.e. it is non-superimposable on its mirror image.

In the given structure, the tetrahedral carbon is attached to four different groups / arranged in such a way that no plane of symmetry exists. Therefore the molecule is chiral.

Hence, the compound is optically active.

So, Statement I is correct.
Check Statement II: "The second structure is mirror image of compound A."

To be the mirror image, every stereocenter must have opposite configuration relative to the original.

On comparing the two drawings, the second structure is not the true mirror image of $A$ ; rather, it can be obtained by a rotation/reorientation mismatch and does not represent inversion at all stereocenter(s) as required for a mirror image.

Therefore, Statement II is incorrect.
Conclusion
- Statement I: Correct
- Statement II: Incorrect
Therefore, the correct option is:

$\boxed{\text{C}}$
Compare with stored answer

Stored correct answer = $\text{C}$ .

Our derived answer matches the stored answer.