0.1 mole of compound ‘S’ will weigh \underline\hspace2cm g. (Given molar mass in g mol−1 C : 12, H : 1, O : 16)

Alcohols Phenols and Ethers PYQ — JEE Main 2025 · 29 Jan · Shift 1 · Q24 with Solution

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Correct answer: 13

To find the mass of $0.1$ mole of compound $S$ , we first need the molar mass of $S$ .

However, the actual structure or molecular formula of compound $S$ is not provided in the question as shown. So the value can only be determined if $S$ is a specific compound known from omitted context.

Given that the stored correct answer is $13$ , let us verify what molar mass that implies.

Step 1: Use the mole–mass relation

\text{mass} = \text{number of moles} \times \text{molar mass}

For $0.1$ mole:

\text{mass} = 0.1 \times M

If the mass is $13\,\text{g}$ , then

13 = 0.1 \times M

So,

M = \frac{13}{0.1} = 130\,\text{g mol}^{-1}

Step 2: Interpret the result

So compound $S$ must have molar mass:

130\,\text{g mol}^{-1}

Then the mass of $0.1$ mole is indeed:

0.1 \times 130 = 13\,\text{g}

Final Answer

\boxed{13}

Since the defining information for compound $S$ is missing in the displayed question, the exact derivation from structure is not possible from the provided data alone. But using the stored answer, the implied molar mass is consistent, and the final integer answer is $13$ .

More from Alcohols Phenols and Ethers

Step 1: Use the mole–mass relation

\text{mass} = \text{number of moles} \times \text{molar mass}

For

0.1

mole:

\text{mass} = 0.1 \times M

If the mass is

13\,\text{g}

, then

13 = 0.1 \times M

So,

M = \frac{13}{0.1} = 130\,\text{g mol}^{-1}

Alcohols Phenols and Ethers question

Alcohols Phenols and Ethers question

Step 1: Use the mole–mass relation

Step 2: Interpret the result

Final Answer

More from Alcohols Phenols and Ethers

Alcohols Phenols and Ethers question

Alcohols Phenols and Ethers question

Step 1: Use the mole–mass relation

Step 2: Interpret the result

Final Answer

More from Alcohols Phenols and Ethers