Identify each reaction of phenol

We match each reactant set in List I with its known product in List II.

(A) Phenol, Zn / $\Delta$

When phenol is heated with zinc dust, the $-OH$ group is removed and phenol is reduced to benzene:

$\mathrm{C_6H_5OH \xrightarrow[\Delta]{Zn} C_6H_6}$

So,

$\boxed{(A) \to (III)\text{ Benzene}}$

(B) Phenol, $\mathrm{CHCl_3}$, NaOH, HCl

This is the Reimer-Tiemann reaction. Phenol on treatment with chloroform and sodium hydroxide, followed by acidification, gives salicylaldehyde (o-hydroxybenzaldehyde) as the major product.

$\mathrm{Phenol \xrightarrow[HCl]{CHCl_3,\,NaOH} Salicylaldehyde}$

So,

$\boxed{(B) \to (I)\text{ Salicylaldehyde}}$

(C) Phenol, $\mathrm{CO_2}$, NaOH, HCl

This is the Kolbe-Schmitt reaction. Sodium phenoxide reacts with carbon dioxide, and after acidification gives salicylic acid (o-hydroxybenzoic acid).

$\mathrm{Phenol \xrightarrow[HCl]{CO_2,\,NaOH} Salicylic\ acid}$

So,

$\boxed{(C) \to (II)\text{ Salicylic acid}}$

(D) Phenol, Conc. $\mathrm{HNO_3}$

Phenol with concentrated nitric acid undergoes nitration to form 2,4,6-trinitrophenol, commonly called picric acid.

$\mathrm{Phenol \xrightarrow{Conc.\ HNO_3} Picric\ acid}$

So,

$\boxed{(D) \to (IV)\text{ Picric acid}}$

Final matching

The correct matching is:

This corresponds to Option B.

Comparison with stored correct answer

Stored correct answer = B

Derived answer = B

Hence, the derived answer agrees with the stored correct answer.