1. Understand Statement I

Phenol is a strongly activating aromatic compound because the $-OH$ group donates electron density to the benzene ring by resonance.

So, phenol undergoes electrophilic bromination very easily.

• In non-polar solvents like $\mathrm{CS_2}$ or $\mathrm{CHCl_3}$, bromination of phenol gives mainly ortho- and para-bromophenol.
• Because the ring is already strongly activated, Lewis acid catalyst is not required.

Therefore, Statement I is false.

2. Understand Statement II

A Lewis acid such as $\mathrm{FeBr_3}$ can polarize $\mathrm{Br_2}$:

More precisely, the Lewis acid makes bromine sufficiently electrophilic, often described in electrophilic substitution as generation of $\mathrm{Br^+}$ (or a bromonium-like electrophile).

Thus, the statement that Lewis acid catalyst polarises bromine to generate $\mathrm{Br^+}$ is conceptually true.

Therefore, Statement II is true.

3. Evaluate options

• A: Statement I true, Statement II false $\rightarrow$ Incorrect
• B: Both true $\rightarrow$ Incorrect
• C: Statement I false, Statement II true $\rightarrow$ Correct
• D: Both false $\rightarrow$ Incorrect

4. Final Answer

The correct option is:

5. Comparison with stored correct answer

Stored correct answer = C

Derived answer = C

So, the derived answer agrees with the stored correct answer.