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Impulse and Momentum question

2008 · Shift 1 · Q53
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  5. /2008 · Shift 1 · Q53

Impulse and Momentum question

2008 · Shift 1 · Q53

JEE AdvancedPhysicsImpulse and MomentumMultiple correct+4 / −2
Two balls, having linear momenta p→1=pi^{\overrightarrow p _1} = p\widehat ip​1​=pi and p→2=−pi^{\overrightarrow p _2} = - p\widehat ip​2​=−pi, undergo a collision in free space. There is no external force acting on the balls. Let p′→1{\overrightarrow {p'} _1}p′​1​ and p′→2{\overrightarrow {p'} _2}p′​2​ be their final momenta. The following option(s) is (are) NOT ALLOWED for any non-zero value of p,a1,a2,b1,b2,c1p,{a_1},{a_2},{b_1},{b_2},{c_1}p,a1​,a2​,b1​,b2​,c1​ and c2{c_2}c2​ :
  1. A
    p′→1=a1i^+b1j^+c1k^;p′→2=a2i^+b2j^{\overrightarrow {p'} _1} = {a_1}\widehat i + {b_1}\widehat j + {c_1}\widehat k;{\overrightarrow {p'} _2} = {a_2}\widehat i + {b_2}\widehat jp′​1​=a1​i+b1​j​+c1​k;p′​2​=a2​i+b2​j​
  2. B
    p′→1=c1k^;p′→2=c2k^{\overrightarrow {p'} _1} = {c_1}\widehat k;{\overrightarrow {p'} _2} = {c_2}\widehat kp′​1​=c1​k;p′​2​=c2​k
  3. C
    p′→1=a1i^+b1j^+c1k^;p′→2=a2i^+b2j^−c1k^{\overrightarrow {p'} _1} = {a_1}\widehat i + {b_1}\widehat j + {c_1}\widehat k;{\overrightarrow {p'} _2} = {a_2}\widehat i + {b_2}\widehat j - {c_1}\widehat kp′​1​=a1​i+b1​j​+c1​k;p′​2​=a2​i+b2​j​−c1​k
  4. D
    p′→1=a1i^+b1j^;p′→2=a2i^+b1j^{\overrightarrow {p'} _1} = {a_1}\widehat i + {b_1}\widehat j;{\overrightarrow {p'} _2} = {a_2}\widehat i + {b_1}\widehat jp′​1​=a1​i+b1​j​;p′​2​=a2​i+b1​j​
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