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Atoms and Nuclei question

2019 · Shift 2 · Q43

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JEE Advanced
Physics
Atoms and Nuclei
2019 · Shift 2 · Q43

Atoms and Nuclei question

2019 · Shift 2 · Q43

JEE AdvancedPhysicsAtoms and NucleiMultiple correct+4 / −1

A free hydrogen atom after absorbing a photon of wavelength

\lambda

a gets excited from the state n = 1 to the state n = 4. Immediately after that the electron jumps to n = m state by emitting a photon of wavelength

\lambda

e. Let the change in momentum of atom due to the absorption and the emission be

\Delta {p_a}

and

\Delta {p_e}

, respectively. If

{{{\lambda _a}} \over {{\lambda _e}}} = {1 \over 5}

, which of the option(s) is/are correct? [Use hc = 1242 eVnm; 1 nm = 10-9 m, h and c are Planck's constant and speed of light in vacuum, respectively]

A
The ratio of kinetic energy of the electron in the state n = m to the state, n = 1 is ${1 \over 4}$
B
m = 2
C
${{\Delta {p_a}} \over {\Delta {p_e}}} = {1 \over 2}$
D
$\lambda$ e = 418 nm

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