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Limits Continuity and Differentiability question

2025 · Shift 1 · Q27
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  5. /2025 · Shift 1 · Q27

Limits Continuity and Differentiability question

2025 · Shift 1 · Q27

JEE AdvancedMathematicsLimits Continuity and DifferentiabilityNumerical+4 / −1
Let α and β be the real numbers such that lim⁡x→01x3(α2∫0x11−t2 dt+βxcos⁡x)=2.\lim\limits_{x \to 0} \frac{1}{x^3} \left( \frac{\alpha}{2} \int\limits_0^x \frac{1}{1-t^2} \, dt + \beta x \cos x \right) = 2.x→0lim​x31​(2α​0∫x​1−t21​dt+βxcosx)=2. Then the value of α + β is ‾\underline{\hspace{2cm}}​.
Numerical answer
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