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Ellipse question

2010 · Shift 2 · Q29
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  5. /2010 · Shift 2 · Q29

Ellipse question

2010 · Shift 2 · Q29

JEE AdvancedMathematicsEllipseMCQ+4 / −1
Tangents are drawn from the point P(3,4)P(3, 4)P(3,4) to the ellipse x29+y24=1{{{x^2}} \over 9} + {{{y^2}} \over 4} = 19x2​+4y2​=1 touching the ellipse at points AAA and BBB. The equation of the locus of the point whose distances from the point PPP and the line ABABAB are equal, is
  1. A
    9x2+y2−6xy−54x−62y+241=09{x^2} + {y^2} - 6xy - 54x - 62y + 241 = 09x2+y2−6xy−54x−62y+241=0
  2. B
    x2+9y2+6xy−54x+62y−241=0{x^2} + 9{y^2} + 6xy - 54x + 62y - 241 = 0x2+9y2+6xy−54x+62y−241=0
  3. C
    9x2+9y2−6xy−54x−62y−241=09{x^2} + 9{y^2} - 6xy - 54x - 62y - 241 = 09x2+9y2−6xy−54x−62y−241=0
  4. D
    x2+y2−2xy+27x+31y−120=0{x^2} + {y^2} - 2xy + 27x + 31y - 120 = 0x2+y2−2xy+27x+31y−120=0
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