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Ellipse question

2009 · Shift 2 · Q36
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Ellipse question

2009 · Shift 2 · Q36

JEE AdvancedMathematicsEllipseMultiple correct+4 / −2
An ellipse intersects the hyperbola 2x2−2y2=12{x^2} - 2{y^2} = 12x2−2y2=1 orthogonally. The eccentricity of the ellipse is reciprocal of that of the hyperbola. If the axes of the ellipse are along the coordinate axes then
  1. A
    equation of ellipse is x2+2y2=2{x^2} + 2{y^2} = 2x2+2y2=2
  2. B
    the foci of ellipse are (±1,0)\left( { \pm 1,0} \right)(±1,0)
  3. C
    equation of ellipse is x2+2y2=4{x^2} + 2{y^2} = 4x2+2y2=4
  4. D
    the foci of ellipse are (±2,0)\left( { \pm \sqrt 2 ,0} \right)(±2​,0)
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