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Definite Integration question

2009 · Shift 2 · Q25
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  5. /2009 · Shift 2 · Q25

Definite Integration question

2009 · Shift 2 · Q25

JEE AdvancedMathematicsDefinite IntegrationMultiple correct+4 / −2
If In=∫−ππsin⁡nx(1+πx)sin⁡xdx,n=0,1,2,{I_n} = \int\limits_{ - \pi }^\pi {{{\sin nx} \over {(1 + {\pi ^x})\sin x}}dx,n = 0,1,2,}In​=−π∫π​(1+πx)sinxsinnx​dx,n=0,1,2, .... then
  1. A
    In=In+2{I_n} = {I_{n + 2}}In​=In+2​
  2. B
    ∑m=110I2m+1=10π\sum\limits_{m = 1}^{10} {{I_{2m + 1}}} = 10\pim=1∑10​I2m+1​=10π
  3. C
    ∑m=110I2m=0\sum\limits_{m = 1}^{10} {{I_{2m}}} = 0m=1∑10​I2m​=0
  4. D
    In=In+1{I_n} = {I_{n + 1}}In​=In+1​
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